Chapter 19.9, Problem 1.2ACP

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Use the energy produced by the combustion of gasoline (46 MJ/kg) to calculate the energy contained in 15 gallons of gasoline. (Assume the density of gasoline is 0.70 kg/L.)

Interpretation Introduction

Interpretation:

The energy contained in 15gallons of gasoline has to be determined if the energy produced by the combustion of gasoline is 46MJ/kg

Concept introduction:

Energy conversions:

• 1gallon=4qt
• 1kg=1.057qt
• 1MJ=kJ

Density=massvolume

Explanation

Given data:

Densityâ€‰ofâ€‰gasolineâ€‰=â€‰0.70â€‰kg/LEneregyâ€‰producedâ€‰byâ€‰theâ€‰combustionâ€‰ofâ€‰gasolineâ€‰=â€‰46â€‰MJ/kgAmountâ€‰ofâ€‰gasolineâ€‰=â€‰15â€‰gallons

Useful data:

1â€‰gallonâ€‰=â€‰4â€‰qt1â€‰kgâ€‰=â€‰1.057â€‰qt

We have to calculate the energy contained in 15â€‰gallons of gasoline.

First we can convert gallons to quarts.

1â€‰gallonâ€‰=â€‰4â€‰qt

Therefore,

=15â€‰gallonsâ€‰Ã—â€‰4â€‰qt1â€‰gallon=â€‰60â€‰qt

Densityâ€‰ofâ€‰gasolineâ€‰=â€‰0.70â€‰kg/L

Density can be converted from kg/Lâ€‰toâ€‰kg/qt

1â€‰kgâ€‰=â€‰1

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