   Chapter 2, Problem 111GQ

Chapter
Section
Textbook Problem

Put the following elements in order from smallest to largest mass:(a) 3.79 × 1024 atoms Fe(b) 19.921 mol H2(c) 8.576 mol C(d) 7.4 mol Si(e) 9.221 mol Na(f) 4.07 × 1024 atoms Al(g) 9.2 mol Cl2

Interpretation Introduction

Interpretation:

The given elements are needed to be arranged in order from smallest to largest mass.

Concept introduction:

Molar masses of Fe,H2, C, Si, Na, Al andCl2 are

55.8g, 2.01g, 12.01g, 28.08g, 23g, 27g and 39g  respectively.

• Conversion formula for mass of an atom into number moles,

Numberofmoles=MassingramsMolarmass

• Equation for finding number of atoms from number of moles of an atom,

Numberofatoms=numberofmolesofatom×6.022×1023atoms/mol

Explanation

(a) 3.79×1024atomsFe

Equation for finding number of atoms from number of moles of an atom,

Numberofatoms=MassingramsMolarmass×6.022×1023atoms/mol

Therefore,

The mass of Fe in the given amount is,

3.79×1024atoms6.022×1023atoms/mol×55.845g/mol=351g

(b) 19.921molH2

Conversion formula for number moles of a molecule into mass,

Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of H2 in the given amount is,

19.921mol×2.01g/mol=40.04g

(c) 8.576molC

Conversion formula for number moles of an atom into mass,

Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of C in the given amount is,

8.576mol×12.01g/mol=103g

(d) 7.4molSi

Conversion formula for number moles of an atom into mass,

Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of silicon in the given amount is,

7.4mol×28.08g/mol=208g

(e) 9.221molNa

Conversion formula for number of moles of an atom into mass,

Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of sodium in the given amount is,

9

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