   Chapter 2, Problem 120GQ

Chapter
Section
Textbook Problem

Ionic and molecular compounds of the halogens.(a) What are the names of BaF2, SiCl4, and NiBr2?(b) Which of the compounds in part (a) are ionic, and which are molecular?(c) Which has the largest mass, 0.50 mol of BaF2, 0.50 mol of SiCl4, or 1.0 mol of NiBr2?

(a)

Interpretation Introduction

Interpretation: For the given three compounds, the names are needed to be determined.

Concept introduction:

• Naming of molecular binary compounds (two element compounds),

The binary compounds of hydrogen with nonmetals are named as hydrogen followed by nonmetals name in ‘ide’ form (add ‘ide’ into stem of the name).

The binary compounds formed by combination of group 4A-7A elements are named as putting the first name as early group elements and last name as late group element in ‘ide’ form. The more than one number of an element is named by adding prefix as “di-, tri-, tetra-, penta- and so on.

• Naming of ions:

Positive ions (cations) are named as metal name, example: aluminum for aluminum cation.

But, for the transition metals the ionic charge also included by roman numerals with the naming of compound.

Negative ions (anions) are named by adding ‘ide’ to the stem of the nonmetal element, from which the anion is formed, example: chloride, bromide, etc.

• Molar masses of BaF2,SiCl4 and NiBr2 are 175.3g, 169.8 and 218.53g respectively.
• Conversion formula for number moles of an atom into mass,

Molarmass×Numberofmoles=Massingrams

Explanation

In BaF2 ionic compound, barium is cation and fluorine is the anion (fluoride).

Hence, BaF2 is named as barium fluoride.

In SiCl4 molecular compound, Si is 4A group element and Cl is 7A group element, silicon is named as silicon and the four Cl are named as tetrachloride

(b)

Interpretation Introduction

Interpretation: For the given three compounds, the ionic and molecular compounds have to be identified.

Concept introduction:

• Naming of molecular binary compounds (two element compounds),

The binary compounds of hydrogen with nonmetals are named as hydrogen followed by nonmetals name in ‘ide’ form (add ‘ide’ into stem of the name).

The binary compounds formed by combination of group 4A-7A elements are named as putting the first name as early group elements and last name as late group element in ‘ide’ form. The more than one number of an element is named by adding prefix as “di-, tri-, tetra-, penta- and so on.

• Naming of ions:

Positive ions (cations) are named as metal name, example: aluminum for aluminum cation.

But, for the transition metals the ionic charge also included by roman numerals with the naming of compound.

Negative ions (anions) are named by adding ‘ide’ to the stem of the nonmetal element, from which the anion is formed, example: chloride, bromide, etc.

• Molar masses of BaF2,SiCl4 and NiBr2 are 175.3g, 169.8 and 218.53g respectively.
• Conversion formula for number moles of an atom into mass,

Molarmass×Numberofmoles=Massingrams

(c)

Interpretation Introduction

Interpretation: For given three compounds, the largest mass containing compound are needed to be determined.

Concept introduction:

• Naming of molecular binary compounds (two element compounds),

The binary compounds of hydrogen with nonmetals are named as hydrogen followed by nonmetals name in ‘ide’ form (add ‘ide’ into stem of the name).

The binary compounds formed by combination of group 4A-7A elements are named as putting the first name as early group elements and last name as late group element in ‘ide’ form. The more than one number of an element is named by adding prefix as “di-, tr-, tetra-, penta- and so on.

• Naming of ions:

Positive ions (cations) are named as metal name, example: aluminum for aluminum cation.

But, for the transition metals the ionic charge also included by roman numerals with the naming of compound.

Negative ions (anions) are named by adding ‘ide’ to the stem of the nonmetal element, from which the anion is formed, example: chloride, bromide, etc.

• Molar masses of BaF2,SiCl4 and NiBr2 are 175.3g, 169.8 and 218.53g respectively.
• Conversion formula for number moles of an atom into mass,

Molarmass×Numberofmoles=Massingrams

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