Chapter 2, Problem 137GQ

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# A compound called MMT was once used to boost the octane rating of gasoline. What is the empirical formula of MMT if it is 49.5% C, 3.2% H, 22.0% O, and 25.2% Mn?

Interpretation Introduction

Interpretation: The empirical formula of the given compound MMT should be determined using given data.

Concept introduction:

• Empirical formula of a compound represents the smallest whole number relative ratio of elements in that compound.
• Equation for number moles from mass and molar mass,

Numberofmoles=MassingramsMolarmass

• Mass percent of elements of a compound is the ratio of mass of element to the mass of whole compound and multiplied with hundred.
Explanation

Given:

Mass percent of carbon, hydrogen, oxygen and manganese in the given compound MMT are 49.5%,â€‰3.2â€‰%,â€‰22.0â€‰%â€‹â€‹â€‹â€‰â€‰â€‰andâ€‰â€‰25.2% respectively.

Mass percent of an element means, 100g of compound contains that mass percent of an element in grams. Therefore, mass of 49.5gâ€‰â€‰ carbon 3.2â€‰gâ€‰ of hydrogen â€‰22.0â€‰gâ€‰â€‰ of oxygen 25.2â€‰g of manganese are present respectively in 100g of MMT.

Equation for number moles from mass and molar mass is,

â€‚Â Numberâ€‰ofâ€‰molesâ€‰â€‰=â€‰â€‰Massâ€‰inâ€‰gramsâ€‰Molarâ€‰mass

Therefore, the number of moles of carbon is,

â€‚Â Numberâ€‰ofâ€‰molesâ€‰â€‰=â€‰â€‰49.5â€‰â€‰g12.01g/molâ€‰=â€‰â€‰4.1215â€‰â€‰mol

The number of moles of hydrogen is,

Â Â Â Â Numberâ€‰ofâ€‰molesâ€‰â€‰=â€‰â€‰â€‰â€‰3.2â€‰â€‰g1â€‰â€‰g/molâ€‰=â€‰â€‰3.2â€‰mol

The number of moles of oxygen is,

Â Â Â Â Numberâ€‰ofâ€‰molesâ€‰â€‰=â€‰â€‰â€‰â€‰22.0â€‰â€‰g16â€‰g/molâ€‰=â€‰â€‰1

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