Chapter 2, Problem 149GQ

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The mass of 2.50 mol of a compound with the formula ECl4, in which E is a nonmetallic element, is 385 g. What is the molar mass of ECl4? What is the identity of E?

Interpretation Introduction

Interpretation: For the given molecule ECl4, the molar mass and the identity of E are needed to be identified.

Concept introduction:

Equation for finding molar mass from mass of a molecule and number moles is,

Molarmass=MassingramsNumberofmoles

• Molar mass of a molecule can be calculated from its molecular formula by taking the sum of atomic masses of all the elements present in it.
• Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12g of 12C.
• The mole is actually quantity of particles that is Avogadro’s number of particles present in elements or compounds.
• The sum of mass of all atoms present in formula of chemical substance is referred as molecular or formula weight of that substance.
• Mass: It is the quantitative measure of a substance. The amount of matter present in substance is expressed as mass. The S.I. unit of mass is kg.
Explanation

The mass and the number of moles of ECl4 is given that 385g and 2.5mol.

Equation for finding molar mass from mass of a molecule and number moles is,

Â Â Â Â Molarâ€‰massâ€‰â€‰=â€‰â€‰Massâ€‰inâ€‰gramsâ€‰Numberâ€‰ofâ€‰molesÂ

Therefore, the molar mass of ECl4 is,

Â Â Â Â Molarâ€‰massâ€‰â€‰=â€‰â€‰385g2

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