University Physics (14th Edition)
14th Edition
ISBN: 9780133969290
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Textbook Question
Chapter 2, Problem 2.86P
DATA A model car starts from rest and travels in a straight line. A smartphone mounted on the car has an app that transmits the magnitude of the car’s acceleration (measured by an accelerometer) every second. The results are given in the table.
| Time (s) | Acceleration ( m/s2) |
| 0 | 5.95 |
| 1.00 | 5.52 |
| 2.00 | 5.08 |
| 3.00 | 4.55 |
| 4.00 | 3.96 |
| 5.00 | 3.40 |
Each measured value has some experimental error, (a) Plot acceleration versus time and find the equation for the straight line that gives the best fit to the data, (b) Use the equation for a(t) that you found in part (a) to calculate υ(t), the speed of the car as a function of time. Sketch the graph of υ versus t. Is this graph a straight line? (c) Use your result from part (b) to calculate the speed of the car at t = 5.00 s. (d) Calculate the distance the car travels between t = 0 and t = 5.00 s.
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An object starts at the origin with an initial velocity of v0 = 10.0 m/s i + 15.0 m/s j. The object is given a constant acceleration of a = 1.00 m/s2 i + 2.00 m/s2 j. (a) Calculate the (x,y) position of the object at t = 10.0 seconds. (b) Calculate the velocity of the object (vx,vy) at t = 10.0 seconds.
A car starts from rest, then accelerates at a constant rate over a distance of 89 m. It then immediately decelerates at a constant rate over a distance of 152 m. The entire trip lasts a total duration of 27.2 s. What were the magnitudes of the car s accelerations for the speedup and slowdown stages respectively?
1. 1.76 m/s^2, then 1.03 m/s^2
2. 3.27 m/s^2, then 5.59 m/s^2
3. 0.65 m/s^2, then 0.65 m/s^2
4. 5.59 m/s^2, then 3.27 m/s^2
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a = ( v2 - v1 )/Δt
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Chapter 2 Solutions
University Physics (14th Edition)
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