Chapter 2, Problem 2.1P

Find the resultant force for each system of forces shown.

To determine

The resultant of the given forces.

Answer to Problem 2.1P

  $78.102\text{lb}$ .

Explanation of Solution

Given information:

Concept used:

Resultant force the two forces is

  $R^2=X^2+Y^2$

Calculation:

In the figure the X is moving in right direction so we will take “+ sign”.

And, the Y is moving in downward direction, so we are taking Y value in “- sign”

The resultant is given by

  $R^2=X^2+Y^2$

  $\begin{array}{l}$ R^2={50}^2+{(-60)}^2$R=\sqrt{{50}^2+{(-60)}^2}\\ R=78.102\mathrm{l}b\end{array}$

Conclusion:

Therefore, the resultant of the given forces is $78.102\text{lb}$.

To determine

The resultant of the given forces.

Answer to Problem 2.1P

  $284.253N$

Explanation of Solution

Given information:

The forces are

Concept used:

Resultant force the two forces is

  $R^2=X^2+Y^2$

Calculation:

In the figure the X is moving in right direction so we will take “+ sign”.

And, the Y is moving in upward direction, so we are taking Y value in “+ sign”

The resultant is given by

   $\begin{array}{l}{R}^2=X^2+Y^2\\ $ R^2={180}^2+{(220)}^2$R=\sqrt{{180}^2+{(220)}^2}\\ R=284.253N\end{array}$

Conclusion:

Therefore, the resultant of the given force is $284.253N$

To determine

The resultant of the given forces.

Answer to Problem 2.1P

  $4.272kips$

Explanation of Solution

Given information:

The given forces are

Concept used:

Resultant force the two forces is

  $R^2=X^2+Y^2$

Calculation:

In the figure the X is moving in left direction so we will take “- sign”.

And, the Y is moving in downward, so we are taking Y value in “- sign”

We know that the resultant is given by

  $\begin{array}{l}{R}^2=X^2+Y^2\\ $ R^2={(-4)}^2+{(-1.5)}^2$R=\sqrt{{(-4)}^2+{(-1.5)}^2}\\ R=4.272kips\end{array}$

Conclusion:

Therefore, the resultant of the given force is $4.272kips$ .