Inorganic Chemistry
Inorganic Chemistry
5th Edition
ISBN: 9780321811059
Author: Gary L. Miessler, Paul J. Fischer, Donald A. Tarr
Publisher: Prentice Hall
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Textbook Question
Chapter 2, Problem 2.1P

Determine the de Brogue wavelength of
a. an electron moving at 1/10 the speed of light.
b. a 400 g Frisbee moving at 10 km/h.
c. an 8.0-pound bowling ball rolling down the lane with a velocity of 2.0 meters per second.
d. a 13.7 g hummingbird flying at a speed of 30.0 miles per hour.

a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:The de Broglie wavelength of electron that has 1/10th speed of light should be determined.

Concept introduction:The de Broglie established a relation for particles of matter that they also can behave as a wave and has a wavelength. The wavelength of particle is inversely related to mass of particle. The smaller the mass, the larger its wavelength.

The expression given by the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of particle.

Answer to Problem 2.1P

The de Broglie wavelength of electron that has 1/10th speed of light is 0.0242 nm .

Explanation of Solution

The expression to calculate the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of mass.

Value of h is 6.625×1034 Jsec .

Value of m is 9.11×1031 kg .

Value of v is 3.0×107 m/s .

Substitute the value in above equation.

  λ=hmv=6.625× 10 34 Jsec( 9.11× 10 31  kg)( 3.0× 10 7  m/s)=(2.42× 10 11 m)( 1 nm 10 9  m)=0.0242 nm

b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:The de Broglie wavelength of 400 g Frisbee thathas 10 km/h speed should be determined.

Concept introduction: de Broglie established a relation for particles of matter that they also can behave as a wave and has a wavelength. The wavelength of particle is inversely related to mass of particle. The smaller the mass, the larger its wavelength.

The expression given by the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of particle.

Answer to Problem 2.1P

The de Broglie wavelength of 400 g Frisbee that has 10 km/h speed is 5.96×1034 m .

Explanation of Solution

The expression to calculate the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of mass.

Value of h is 6.625×1034 Jsec .

Value of m is 400 g .

Value of v is 10 km/h .

Substitute the values in above equation.

  λ=hmv=( 6.625× 10 34  Jsec ( 400 g )( 10 km/h ))( 10 3  g 1 kg)( 1 km 10 3  m)( 3600 sec 1 h)=5.96×1034 m

c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:The de Broglie wavelength of 8.0 lb bowling ballthat has 2.0 m/sec speed should be determined.

Concept introduction: de Broglie established a relation for particles of matter that they also can behave as a wave and has a wavelength. The wavelength of particle is inversely related to mass of particle. The smaller the mass, the larger its wavelength.

The expression given by the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of particle.

Answer to Problem 2.1P

The de Broglie wavelength of 8.0 lb bowling ball that has 2.0 m/sec speed is 9.13×1035 m .

Explanation of Solution

The expression to calculate the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of mass.

Value of h is 6.625×1034 Jsec .

Value of m is 8.0 lb .

Value of v is 2.0 m/sec .

Substitute the value in above equation.

  λ=hmv=( 6.625× 10 34  Jsec ( 8.0 lb )( 2.0 m/sec ))( 1 lb 453.592 g)( 10 3  g 1 kg)=9.13×1035 m

d)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:The de Broglie wavelength of 13.7 g birdthat has 30.0 mi/hr speed should be determined.

Concept introduction: de Broglie established a relation for particles of matter that they also can behave as a wave and has a wavelength. The wavelength of particle is inversely related to mass of particle. The smaller the mass, the larger its wavelength.

The expression given by the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of particle.

Answer to Problem 2.1P

The de Broglie wavelength of 13.7 g bird that has 30.0 mi/hr speed is 3.6×1036 m .

Explanation of Solution

The expression to calculate the de Broglie is as follows:

  λ=hmv

Where,

  • λ is a wavelength of particle.
  • h is a Plank’s constant.
  • m is a mass of particle.
  • v is a velocity of mass.

Value of h is 6.625×1034 Jsec .

Value of m is 13.7 g .

Value of v is 30.0 mi/hr .

Substitute the value in above equation.

  λ=hmv=( 6.625× 10 34  Jsec ( 13.7 g )( 30.0 mi/hr ))( 1 mi 1609.34 m)( 3600 sec 1 h)=3.6×1036 m

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08:55

Chapter 2 Solutions

Inorganic Chemistry

Ch. 2 - The transition from the n=7 to the n=2 level of...Ch. 2 - Emissions are observed at wavelengths of 383.65...Ch. 2 - What is the least amount of energy that can be...Ch. 2 - Hydrogen atom emission spectra measured from the...Ch. 2 - The Rydberg constant equation has two terms that...Ch. 2 - For the 3pz and 4dxz hydrogen-like atomic...Ch. 2 - Repeat the exercise in Problem 2.7 for the 4s and...Ch. 2 - Repeat the exercise in Problem 2.7 for the 5s and...Ch. 2 - The 4fz(x2y2) orbital has the angular function...Ch. 2 - Prob. 2.13PCh. 2 - The label for an fz2 orbital, like that for a dz2...Ch. 2 - a. Determine the possible values for the l and ml...Ch. 2 - a. What are the values of quantum numbers I and n...Ch. 2 - a. At most, how many electrons in an atom can have...Ch. 2 - Determine the Coulombic and exchange energies for...Ch. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - What states are possible for a d3 configuration?...Ch. 2 - Provide explanations of the following phenomena:...Ch. 2 - Give electron configurations for the following:...Ch. 2 - Predict the electron configurations of the...Ch. 2 - Radial probability plots shed insight on issues of...Ch. 2 - Briefly explain the following on the basis of...Ch. 2 - Briefly explain the following on the basis of...Ch. 2 - a. Which 2+ ion has two 3d electrons? Which has...Ch. 2 - A sample calculation in this chapter showed that,...Ch. 2 - Ionization energies should depend on the effective...Ch. 2 - Prepare a diagram such as the one in Figure (a)...Ch. 2 - Why are the ionization energies of the alkali...Ch. 2 - The second ionization of carbon (C+C2++e) and the...Ch. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - The second ionization energy involves removing an...Ch. 2 - Prob. 2.38PCh. 2 - On the basis of electron configurations, explain...Ch. 2 - a. The graph of ionization energy versus atomic...Ch. 2 - The second ionization energy of He ¡s almost...Ch. 2 - The size of the transition-metal atoms decreases...Ch. 2 - Predict the largest and smallest radius in each...Ch. 2 - Select the best choice, and briefly indicate the...Ch. 2 - Select the best choice, and briefly indicate the...Ch. 2 - There are a number of Web sites that display...Ch. 2 - Prob. 2.47P
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