
Concept explainers
How many hydrogen atoms are present in a molecule of each of the compounds in Problem 13-26?
- a. 2-methylcyclopentene
- b. 1,3-cyclopentadiene
- c. 2,3-dimethylpentane
- d. 1-ethyl-2-methylcyclohexene
(a)

Interpretation:
The total number of hydrogen atoms present in the given molecule has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Alkanes are a class of saturated hydrocarbons that do not contain a ring of carbon atoms but a chain of carbon atoms with carbon‑carbon single bonds. The general molecular formula for alkanes is
Alkenes and cycloalkenes are a class of unsaturated hydrocarbons that contain at least one double bond in its structure. The general molecular formula for alkene with one double bond is
Answer to Problem 2.28EP
The total number of hydrogen atoms present is 10.
Explanation of Solution
Cycloalkenes are unsaturated hydrocarbons that contain at least one double bond between carbon atoms with ring structure. The general molecular formula for cycloalkene with one double bond is
Carbon atoms are present at the intersection and at the end points. The above structure has five intersections and one end point. Therefore, there is a total of six carbon atoms. The total number of hydrogen atoms can be found by substituting in the general molecular formula as shown below,
The total number of hydrogen atoms that will be present in the given cycloalkene is found to be ten.
The total number of hydrogen atoms present in the molecule is ten.
(b)

Interpretation:
The total number of hydrogen atoms present in the given molecule has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Alkanes are a class of saturated hydrocarbons that do not contain a ring of carbon atoms but a chain of carbon atoms with carbon‑carbon single bonds. The general molecular formula for alkanes is
Alkenes and cycloalkenes are a class of unsaturated hydrocarbons that contain at least one double bond in its structure. The general molecular formula for alkene with one double bond is
Answer to Problem 2.28EP
The total number of hydrogen atoms present is 6.
Explanation of Solution
Cycloalkenes are unsaturated hydrocarbons that contain at least one double bond between carbon atoms with a ring structure. The general molecular formula for cycloalkene with two double bond is
Carbon atoms are present at the intersection and at the end points. The above structure has five intersections and no end points. Therefore, there is a total of five carbon atoms. The total number of hydrogen atoms can be found by substituting in the general molecular formula as shown below,
The total number of hydrogen atoms that will be present in the given cycloalkene is found to be six.
The total number of hydrogen atoms present in the molecule is six.
(c)

Interpretation:
The total number of hydrogen atoms present in the given molecule has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Alkanes are a class of saturated hydrocarbons that do not contain a ring of carbon atoms but a chain of carbon atoms with carbon‑carbon single bonds. The general molecular formula for alkanes is
Alkenes and cycloalkenes are a class of unsaturated hydrocarbons that contain at least one double bond in its structure. The general molecular formula for alkene with one double bond is
Answer to Problem 2.28EP
The total number of hydrogen atoms present is 16.
Explanation of Solution
Alkanes are saturated hydrocarbons that contain only single bonds between carbon atoms with no ring structure. The general molecular formula for alkane is
Carbon atoms are present at the intersection and at the end points. The above structure has three intersections and four end points. Therefore, there is a total of seven carbon atoms. The total number of hydrogen atoms can be found by substituting in the general molecular formula as shown below,
The total number of hydrogen atoms that will be present in the given alkane is found to be sixteen.
The total number of hydrogen atoms present in the molecule is sixteen.
(d)

Interpretation:
The total number of hydrogen atoms present in the given molecule has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Alkanes are a class of saturated hydrocarbons that do not contain a ring of carbon atoms but a chain of carbon atoms with carbon‑carbon single bonds. The general molecular formula for alkanes is
Alkenes and cycloalkenes are a class of unsaturated hydrocarbons that contain at least one double bond in its structure. The general molecular formula for alkene with one double bond is
Answer to Problem 2.28EP
The total number of hydrogen atoms present is 16.
Explanation of Solution
Cycloalkenes are unsaturated hydrocarbons that contain at least one double bond between carbon atoms with ring structure. The general molecular formula for cycloalkene with one double bond is
Carbon atoms are present at the intersection and at the end points. The above structure has seven intersections and two end points. Therefore, there is a total of nine carbon atoms. The total number of hydrogen atoms can be found by substituting in the general molecular formula as shown below,
The total number of hydrogen atoms that will be present in the given cycloalkene is found to be sixteen.
The total number of hydrogen atoms present in the molecule is sixteen.
Want to see more full solutions like this?
Chapter 2 Solutions
Organic And Biological Chemistry
- MBA WAZIMO IMA 4. Convert the following structure to a line-angle structure. Jnem HHHH | \/ HCC CH \/\/\/\/ HOCO Corts bns H:02 HD bis inol296 CC 00005 wlbnd bilegno12 sdt ai rbidWytibios ni bevisa C CH HH / \ // \ HCH H Sytibios evitsisi ni gonsarrow_forwardLT SET 10. Synthesize the following compound beginning with acetylene. You may use any readily available organic or inorganic reactants. Show all steps and all conditions for each step. H CH3 CH اسarrow_forwardA For the best experi Draw the product of the reaction shown below. Ignore inorganic byproducts. + H NaBH4 CH3CH2OH Drawingarrow_forward
- For the best experier Draw the product of the reaction shown below. Ignore inorganic byproducts. + Br 1. LiAlH4 2. H₂O Drawing Drarrow_forwardDraw the following reaction scheme. Include all atoms, bonds, reaction arrows, names, ions, charges, etc. OCH3 H H H methyl acetate QUESTION 2 (5pts): Draw the following compounds. a) b) H H + HÖCH3 methanol CHO HIIII.. C H3C CH₂OHarrow_forwardDraw the following intermediate. Be sure to use curved arrows, rather than straight reaction arrows to show electron movement. OH да QUESTION 4 (10pts): Flip through your textbook. Choose a mechanism and replicate it. Make sure to include all atoms, bonds, reaction arrows, names, ions, charges, curved arrows, etc. Remember mechanisms show the movement of electrons. The curved arrows are important. Some mechanisms you may find: Aldol Condensation Benzilic Acid Rearrangement Clemmensen Reduction Elimination Reaction (E1 or E2) Fischer Indole Synthesis Grignard Reaction Hydroboration-Oxidation Michael Addition Strecker Synthesis Acetoacetic Ester Synthesis Baeyer-Villiger Oxidation Birch Reduction Dieckmann Condensation Oxymercuration-Demercuration Friedel-Crafts Acylation Haloform Reaction Malonic Ester Synthesis Esterification Wittig Reaction Aldol Addition Benzoin Condensation Claisen Condensation Diels-Alder Reaction Epoxidation Friedel-Crafts Alkylation Ene Reaction Mannich Reaction…arrow_forward
- Write the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 2 3 4 LO 5 CO 6 7 Hint: you do not need to know the name or symbol of the highlighted element! He Ne Ar Kr Xe Rn Хarrow_forwardExplain how the polarity of the compounds yields an expected order of elution (Caffeine, Benzoic acid, oxalic acid, salicyclic acid). You will need to bring in structure images of the compounds and explain how the polarity of each compound is relative to one another. Be complete, add as needed.arrow_forwardWhich of the given compounds does not produce benzoic acid when treated with potassium permanganate (KMnO4) in the presence of a strong base and heat? (A) diclorofenilmetanol (B) fenilmetanol (C) 2-fenilheptano (D) 1-fenil heptanolarrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning




