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Chemistry for Today: General, Orga...

9th Edition
Spencer L. Seager + 2 others
Publisher: Cengage Learning
ISBN: 9781305960060

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BuyFindarrow_forward

Chemistry for Today: General, Orga...

9th Edition
Spencer L. Seager + 2 others
Publisher: Cengage Learning
ISBN: 9781305960060
Chapter 2, Problem 2.32E
Textbook Problem
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A flammable gas is known to contain only carbon and hydrogen. Its molecular weight is determined and found to be 28.05 u . Which of the following is the likely identity of the gas? Acetylene ( C 2 H 2 ) , ethylene ( C 2 H 4 ) , ethane ( C 2 H 6 ) .

Interpretation Introduction

Interpretation:

Among the given gases, a flammable gas that corresponds to the molecular weight 28.05u is to be predicted.

Concept introduction:

The total number of protons and neutron which are present in an atom is collectively known as atomic mass of that atom. The total number of protons present in the nucleus of an atom is known as atomic number of that atom.

The sum of the masses of the atoms present in a molecule is known as the molecular weight.

Explanation of Solution

The given molecular weight of a gas is 28.05u.

According to the periodic table, the atomic weight of one carbon atom is 12.01u and the atomic mass of one hydrogen atom is 1.008u. According to the given oxides, acetylene (C2H2), ethylene (C2H4), ethane (C2H6), the experimentally obtained molecular weight occurs due to the presence of two carbon atoms.

Thus, the molecular weight of two carbon atoms that is present in a gas is calculated as,

Molecularweightofcarbon present in gas =28.05u2×(atomicmass ofC)

Substitute the value of atomic weight of one carbon atom in the above expression.

Molecularweightofcarbon present in gas =28

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Chapter 2 Solutions

Chemistry for Today: General, Organic, and Biochemistry
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