Organic And Biological Chemistry
Organic And Biological Chemistry
7th Edition
ISBN: 9781305081079
Author: STOKER, H. Stephen (howard Stephen)
Publisher: Cengage Learning,
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Chapter 2, Problem 2.38EP

(a)

Interpretation Introduction

Interpretation:

The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry.  The carbon atoms that have only single bonds attached to it will have tetrahedral geometry.  The carbon atoms that have a triple bond attached to it will have a linear geometry.

(a)

Expert Solution
Check Mark

Answer to Problem 2.38EP

The spatial arrangement is identified as tetrahedral.

Explanation of Solution

Given structure is,

Organic And Biological Chemistry, Chapter 2, Problem 2.38EP , additional homework tip  1

Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond.  This carbon atom has only four single bonds (three with hydrogen and one with carbon atom).  Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.

Conclusion

The spatial arrangement of the left-most carbon atom is identified.

(b)

Interpretation Introduction

Interpretation:

The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry.  The carbon atoms that have only single bonds attached to it will have tetrahedral geometry.  The carbon atoms that have a triple bond attached to it will have a linear geometry.

(b)

Expert Solution
Check Mark

Answer to Problem 2.38EP

The spatial arrangement is identified as tetrahedral.

Explanation of Solution

Given structure is,

Organic And Biological Chemistry, Chapter 2, Problem 2.38EP , additional homework tip  2

Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond.  This carbon atom has only four single bonds (three with hydrogen and one with carbon atom).  Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.

Conclusion

The spatial arrangement of the left-most carbon atom is identified.

(c)

Interpretation Introduction

Interpretation:

The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry.  The carbon atoms that have only single bonds attached to it will have tetrahedral geometry.  The carbon atoms that have a triple bond attached to it will have a linear geometry.

(c)

Expert Solution
Check Mark

Answer to Problem 2.38EP

The spatial arrangement is identified as trigonal planar.

Explanation of Solution

Given structure is,

Organic And Biological Chemistry, Chapter 2, Problem 2.38EP , additional homework tip  3

Looking into the left most carbon atom present in the given structure, it is bonded to one double bond.  This carbon atom has only two single bonds with hydrogen and a double bond with carbon atom.  Therefore, the spatial arrangement of the left-most carbon atom is trigonal planar.

Conclusion

The spatial arrangement of the left-most carbon atom is identified.

(d)

Interpretation Introduction

Interpretation:

The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry.  The carbon atoms that have only single bonds attached to it will have tetrahedral geometry.  The carbon atoms that have a triple bond attached to it will have a linear geometry.

(d)

Expert Solution
Check Mark

Answer to Problem 2.38EP

The spatial arrangement is identified as tetrahedral.

Explanation of Solution

Given structure is,

Organic And Biological Chemistry, Chapter 2, Problem 2.38EP , additional homework tip  4

Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond.  This carbon atom has only four single bonds (three with hydrogen and one with carbon atom).  Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.

Conclusion

The spatial arrangement of the left-most carbon atom is identified.

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Chapter 2 Solutions

Organic And Biological Chemistry

Ch. 2.3 - Prob. 4QQCh. 2.4 - Prob. 1QQCh. 2.4 - Prob. 2QQCh. 2.5 - Prob. 1QQCh. 2.5 - Prob. 2QQCh. 2.5 - Prob. 3QQCh. 2.6 - Prob. 1QQCh. 2.6 - Prob. 2QQCh. 2.6 - Prob. 3QQCh. 2.7 - Prob. 1QQCh. 2.7 - Prob. 2QQCh. 2.7 - Prob. 3QQCh. 2.8 - Prob. 1QQCh. 2.8 - Prob. 2QQCh. 2.9 - Prob. 1QQCh. 2.9 - Prob. 2QQCh. 2.10 - Prob. 1QQCh. 2.10 - Prob. 2QQCh. 2.10 - Prob. 3QQCh. 2.10 - Prob. 4QQCh. 2.10 - Prob. 5QQCh. 2.11 - Prob. 1QQCh. 2.11 - Prob. 2QQCh. 2.11 - Prob. 3QQCh. 2.11 - Prob. 4QQCh. 2.11 - Prob. 5QQCh. 2.12 - Prob. 1QQCh. 2.12 - Prob. 2QQCh. 2.12 - Prob. 3QQCh. 2.12 - Prob. 4QQCh. 2.12 - Prob. 5QQCh. 2.13 - Prob. 1QQCh. 2.13 - Prob. 2QQCh. 2.13 - Prob. 3QQCh. 2.14 - Prob. 1QQCh. 2.14 - Prob. 2QQCh. 2.14 - Prob. 3QQCh. 2.14 - Prob. 4QQCh. 2.15 - Prob. 1QQCh. 2.15 - Prob. 2QQCh. 2.15 - Prob. 3QQCh. 2.15 - Prob. 4QQCh. 2.16 - Prob. 1QQCh. 2.16 - Prob. 2QQCh. 2 - Classify each of the following hydrocarbons as...Ch. 2 - Prob. 2.2EPCh. 2 - Prob. 2.3EPCh. 2 - Prob. 2.4EPCh. 2 - Prob. 2.5EPCh. 2 - Prob. 2.6EPCh. 2 - Prob. 2.7EPCh. 2 - Characterize the physical properties of saturated...Ch. 2 - Prob. 2.9EPCh. 2 - Prob. 2.10EPCh. 2 - Prob. 2.11EPCh. 2 - Prob. 2.12EPCh. 2 - Prob. 2.13EPCh. 2 - Prob. 2.14EPCh. 2 - What is the name of the spatial arrangement for...Ch. 2 - Prob. 2.16EPCh. 2 - Prob. 2.17EPCh. 2 - Prob. 2.18EPCh. 2 - Draw a condensed structural formula for each of...Ch. 2 - Prob. 2.20EPCh. 2 - The following names are incorrect by IUPAC rules....Ch. 2 - The following names are incorrect by IUPAC rules....Ch. 2 - Prob. 2.23EPCh. 2 - Draw a condensed structural formula for each of...Ch. 2 - Prob. 2.25EPCh. 2 - Classify each of the following compounds as...Ch. 2 - Prob. 2.27EPCh. 2 - How many hydrogen atoms are present in a molecule...Ch. 2 - Draw a line-angle structural formula for each of...Ch. 2 - Draw a line-angle structural formula for each of...Ch. 2 - Prob. 2.31EPCh. 2 - Prob. 2.32EPCh. 2 - Prob. 2.33EPCh. 2 - Prob. 2.34EPCh. 2 - Prob. 2.35EPCh. 2 - Prob. 2.36EPCh. 2 - Prob. 2.37EPCh. 2 - Prob. 2.38EPCh. 2 - For each of the following pairs of alkenes,...Ch. 2 - For each of the following pairs of alkenes,...Ch. 2 - Prob. 2.41EPCh. 2 - Prob. 2.42EPCh. 2 - Prob. 2.43EPCh. 2 - Prob. 2.44EPCh. 2 - Prob. 2.45EPCh. 2 - Prob. 2.46EPCh. 2 - For each molecule, indicate whether cistrans...Ch. 2 - Prob. 2.48EPCh. 2 - Prob. 2.49EPCh. 2 - Prob. 2.50EPCh. 2 - Draw a structural formula for each of the...Ch. 2 - Prob. 2.52EPCh. 2 - Prob. 2.53EPCh. 2 - For each of the following molecules, indicate...Ch. 2 - Prob. 2.55EPCh. 2 - Prob. 2.56EPCh. 2 - Prob. 2.57EPCh. 2 - Prob. 2.58EPCh. 2 - Prob. 2.59EPCh. 2 - How many isoprene units are present in a....Ch. 2 - Prob. 2.61EPCh. 2 - Indicate whether each of the following statements...Ch. 2 - Prob. 2.63EPCh. 2 - Prob. 2.64EPCh. 2 - Prob. 2.65EPCh. 2 - Prob. 2.66EPCh. 2 - Prob. 2.67EPCh. 2 - Prob. 2.68EPCh. 2 - Prob. 2.69EPCh. 2 - Prob. 2.70EPCh. 2 - Prob. 2.71EPCh. 2 - Prob. 2.72EPCh. 2 - Prob. 2.73EPCh. 2 - Prob. 2.74EPCh. 2 - Prob. 2.75EPCh. 2 - Prob. 2.76EPCh. 2 - Supply the structural formula of the product in...Ch. 2 - Prob. 2.78EPCh. 2 - Prob. 2.79EPCh. 2 - What reactant would you use to prepare each of the...Ch. 2 - Prob. 2.81EPCh. 2 - Prob. 2.82EPCh. 2 - Prob. 2.83EPCh. 2 - Prob. 2.84EPCh. 2 - Prob. 2.85EPCh. 2 - Prob. 2.86EPCh. 2 - Prob. 2.87EPCh. 2 - Prob. 2.88EPCh. 2 - Prob. 2.89EPCh. 2 - Prob. 2.90EPCh. 2 - Prob. 2.91EPCh. 2 - Prob. 2.92EPCh. 2 - Prob. 2.93EPCh. 2 - Prob. 2.94EPCh. 2 - Prob. 2.95EPCh. 2 - Prob. 2.96EPCh. 2 - Prob. 2.97EPCh. 2 - Prob. 2.98EPCh. 2 - Prob. 2.99EPCh. 2 - Prob. 2.100EPCh. 2 - Prob. 2.101EPCh. 2 - Prob. 2.102EPCh. 2 - Prob. 2.103EPCh. 2 - Prob. 2.104EPCh. 2 - Prob. 2.105EPCh. 2 - Prob. 2.106EPCh. 2 - Prob. 2.107EPCh. 2 - Prob. 2.108EPCh. 2 - Assign each of the compounds in Problem 13-107 an...Ch. 2 - Assign each of the compounds in Problem 13-108 an...Ch. 2 - Prob. 2.111EPCh. 2 - Prob. 2.112EPCh. 2 - Prob. 2.113EPCh. 2 - Prob. 2.114EPCh. 2 - Prob. 2.115EPCh. 2 - Prob. 2.116EPCh. 2 - Prob. 2.117EPCh. 2 - Prob. 2.118EPCh. 2 - Prob. 2.119EPCh. 2 - Prob. 2.120EPCh. 2 - Prob. 2.121EPCh. 2 - Prob. 2.122EPCh. 2 - Prob. 2.123EPCh. 2 - Prob. 2.124EPCh. 2 - Prob. 2.125EPCh. 2 - Prob. 2.126EPCh. 2 - Prob. 2.127EPCh. 2 - Prob. 2.128EPCh. 2 - Prob. 2.129EPCh. 2 - Prob. 2.130EP
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