Concept explainers
(a)
To find:The value of limits.
(a)
Answer to Problem 23RE
The value for each limit is calculated.
Explanation of Solution
Given information:
The given function is
Calculation:
For
For
The left limit
Recollect the result
Using the result, the limit of the function
So, the value of
For
So, the limit for
For
So, the limit for
The left limit
Recollect the result
Using the result, the limit of the function
So, the value of
Therefore, the value for each limit is calculated.
(b)
To find:The discontinuous function
(b)
Answer to Problem 23RE
The function has discontinuous at
Explanation of Solution
Given information:
The given function is
Calculation:
The function is said to be discontinuous at
Using the part
Therefore, the function
Using the part
Hence, the function is not continuous at
Therefore, the function has discontinuous at
(c)
To graph: For the function
(c)
Explanation of Solution
Given information:
The given function is
Graph:
The graph for the given function is shown in figure (1).
Figure (1)
Interpretation: Graph for the function
Chapter 2 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning