BuyFindarrow_forward

Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079

Solutions

Chapter
Section
BuyFindarrow_forward

Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079
Textbook Problem

For each molecule, indicate whether cis–trans isomers exist. If they do, draw the two isomers and label them as cis and trans.

  1. a. CH3 — CH2 — CH=CH2

Chapter 2, Problem 2.48EP, For each molecule, indicate whether cistrans isomers exist. If they do, draw the two isomers and

  1. b. 2-Pentene
  2. c. 1,2-Dichloroethene

(a)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Explanation

Given molecule is,

On seeing the structure of the alkene given above, it is found that two hydrogen atoms are present on the same carbon that is present on the double bond...

(b)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(c)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(d)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomers exist has to be indicated and if it exists the isomers has to be drawn..

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started
Sect-2.3 P-4QQSect-2.4 P-1QQSect-2.4 P-2QQSect-2.5 P-1QQSect-2.5 P-2QQSect-2.5 P-3QQSect-2.6 P-1QQSect-2.6 P-2QQSect-2.6 P-3QQSect-2.7 P-1QQSect-2.7 P-2QQSect-2.7 P-3QQSect-2.8 P-1QQSect-2.8 P-2QQSect-2.9 P-1QQSect-2.9 P-2QQSect-2.10 P-1QQSect-2.10 P-2QQSect-2.10 P-3QQSect-2.10 P-4QQSect-2.10 P-5QQSect-2.11 P-1QQSect-2.11 P-2QQSect-2.11 P-3QQSect-2.11 P-4QQSect-2.11 P-5QQSect-2.12 P-1QQSect-2.12 P-2QQSect-2.12 P-3QQSect-2.12 P-4QQSect-2.12 P-5QQSect-2.13 P-1QQSect-2.13 P-2QQSect-2.13 P-3QQSect-2.14 P-1QQSect-2.14 P-2QQSect-2.14 P-3QQSect-2.14 P-4QQSect-2.15 P-1QQSect-2.15 P-2QQSect-2.15 P-3QQSect-2.15 P-4QQSect-2.16 P-1QQSect-2.16 P-2QQCh-2 P-2.1EPCh-2 P-2.2EPCh-2 P-2.3EPCh-2 P-2.4EPCh-2 P-2.5EPCh-2 P-2.6EPCh-2 P-2.7EPCh-2 P-2.8EPCh-2 P-2.9EPCh-2 P-2.10EPCh-2 P-2.11EPCh-2 P-2.12EPCh-2 P-2.13EPCh-2 P-2.14EPCh-2 P-2.15EPCh-2 P-2.16EPCh-2 P-2.17EPCh-2 P-2.18EPCh-2 P-2.19EPCh-2 P-2.20EPCh-2 P-2.21EPCh-2 P-2.22EPCh-2 P-2.23EPCh-2 P-2.24EPCh-2 P-2.25EPCh-2 P-2.26EPCh-2 P-2.27EPCh-2 P-2.28EPCh-2 P-2.29EPCh-2 P-2.30EPCh-2 P-2.31EPCh-2 P-2.32EPCh-2 P-2.33EPCh-2 P-2.34EPCh-2 P-2.35EPCh-2 P-2.36EPCh-2 P-2.37EPCh-2 P-2.38EPCh-2 P-2.39EPCh-2 P-2.40EPCh-2 P-2.41EPCh-2 P-2.42EPCh-2 P-2.43EPCh-2 P-2.44EPCh-2 P-2.45EPCh-2 P-2.46EPCh-2 P-2.47EPCh-2 P-2.48EPCh-2 P-2.49EPCh-2 P-2.50EPCh-2 P-2.51EPCh-2 P-2.52EPCh-2 P-2.53EPCh-2 P-2.54EPCh-2 P-2.55EPCh-2 P-2.56EPCh-2 P-2.57EPCh-2 P-2.58EPCh-2 P-2.59EPCh-2 P-2.60EPCh-2 P-2.61EPCh-2 P-2.62EPCh-2 P-2.63EPCh-2 P-2.64EPCh-2 P-2.65EPCh-2 P-2.66EPCh-2 P-2.67EPCh-2 P-2.68EPCh-2 P-2.69EPCh-2 P-2.70EPCh-2 P-2.71EPCh-2 P-2.72EPCh-2 P-2.73EPCh-2 P-2.74EPCh-2 P-2.75EPCh-2 P-2.76EPCh-2 P-2.77EPCh-2 P-2.78EPCh-2 P-2.79EPCh-2 P-2.80EPCh-2 P-2.81EPCh-2 P-2.82EPCh-2 P-2.83EPCh-2 P-2.84EPCh-2 P-2.85EPCh-2 P-2.86EPCh-2 P-2.87EPCh-2 P-2.88EPCh-2 P-2.89EPCh-2 P-2.90EPCh-2 P-2.91EPCh-2 P-2.92EPCh-2 P-2.93EPCh-2 P-2.94EPCh-2 P-2.95EPCh-2 P-2.96EPCh-2 P-2.97EPCh-2 P-2.98EPCh-2 P-2.99EPCh-2 P-2.100EPCh-2 P-2.101EPCh-2 P-2.102EPCh-2 P-2.103EPCh-2 P-2.104EPCh-2 P-2.105EPCh-2 P-2.106EPCh-2 P-2.107EPCh-2 P-2.108EPCh-2 P-2.109EPCh-2 P-2.110EPCh-2 P-2.111EPCh-2 P-2.112EPCh-2 P-2.113EPCh-2 P-2.114EPCh-2 P-2.115EPCh-2 P-2.116EPCh-2 P-2.117EPCh-2 P-2.118EPCh-2 P-2.119EPCh-2 P-2.120EPCh-2 P-2.121EPCh-2 P-2.122EPCh-2 P-2.123EPCh-2 P-2.124EPCh-2 P-2.125EPCh-2 P-2.126EPCh-2 P-2.127EPCh-2 P-2.128EPCh-2 P-2.129EPCh-2 P-2.130EP

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

Name two essential fatty acids, and explain why they are called essential.

Chemistry for Today: General, Organic, and Biochemistry

The senses cannot be completely relied on. Why?

An Introduction to Physical Science

A child who ate cream of broccoli soup and became ill now feels ill whenever it is served. The child most likel...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

Argon enters a turbine at a rate of 80.0 kg/min, a temperature of 800C, and a pressure of 1.50 MPa. It expands ...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Which elements are created in stellar nucleosynthesis?

Foundations of Astronomy (MindTap Course List)

If the holdfast of this alga breaks free in a storm, will the organism die?

Oceanography: An Invitation To Marine Science, Loose-leaf Versin