CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
14th Edition
ISBN: 9781259327933
Author: Burdge
Publisher: MCG
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Question
Chapter 2, Problem 2.68QP

A

Interpretation Introduction

Interpretation:

The symbols for each atom has to be identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons.  The strongest nuclear force binds the particles tightly.  Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between columbic repulsion and the short-range attraction.  If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides.  If the attractive forces prevail, the nucleus is stable.

A

Expert Solution
Check Mark

Answer to Problem 2.68QP

The symbol for given atom is C612

Explanation of Solution

To Identify: The symbols for each atom to be identified.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

The element symbol : ZAX,Z (atomic number) = no. of protons. (protons = electrons)= 6.A (mass number) = no.of protons + no.of  neutrons.                           = 6 + 6 = 12The symbol: 612C.

The number of electron is equal to the number proton in the nucleus, thus the 6 electrons is same as 6 protons. The sum of protons and neutrons in the nucleus give the mass number of an element. The atomic number 6 indicates the element is Carbon. The represented symbol is 612C.

B

Interpretation Introduction

Interpretation:

The symbols for each atom has to be identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons.  The strongest nuclear force binds the particles tightly.  Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between columbic repulsion and the short-range attraction.  If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides.  If the attractive forces prevail, the nucleus is stable.

B

Expert Solution
Check Mark

Answer to Problem 2.68QP

The symbol for given atom is N1118a

Explanation of Solution

To Identify: The symbols for each atom to be identified.

Identify the symbol of an element.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

The element symbol : ZAX,Z (atomic number) = no. of protons. (protons = electrons)= 11.A (mass number) = no.of protons + no.of  neutrons.                           = 11 + 7 = 18.The symbol: 1118Na.

The number of electron is equal to the number proton in the nucleus, thus the 11 electrons is same as 11 protons. The sum of protons and neutrons in the nucleus give the mass number of an element. The atomic number 11 indicates the element is Sodium. The represented symbol is 1118Na.

C

Interpretation Introduction

Interpretation:

The symbols for each atom has to be identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons.  The strongest nuclear force binds the particles tightly.  Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between columbic repulsion and the short-range attraction.  If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides.  If the attractive forces prevail, the nucleus is stable.

C

Expert Solution
Check Mark

Answer to Problem 2.68QP

No neutrons number is given. No symbol is determined.

Explanation of Solution

To Identify: The symbols for each atom to be identified.

Identify the symbol of an element.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

The element symbol : ZAX,Z (atomic number) = no. of protons. (protons = electrons)= 29.A (mass number) = no.of protons + no.of  neutrons.                           = 29 + no neutron value is given.The symbol cannot be predicted without the mass number(no number of neutronis given).

The number of electron is equal to the number proton in the nucleus, thus the 29 electrons is same as 29 protons. The sum of protons and neutrons in the nucleus give the mass number of an element. The element symbol cannot be predicted without the mass number because number of neutrons is not given.

D

Interpretation Introduction

Interpretation:

The symbols for each atom has to be identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons.  The strongest nuclear force binds the particles tightly.  Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between columbic repulsion and the short-range attraction.  If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides.  If the attractive forces prevail, the nucleus is stable.

D

Expert Solution
Check Mark

Answer to Problem 2.68QP

The symbol for given atom is K3683r

Explanation of Solution

To Identify: The symbols for each atom to be identified.

Identify the symbol of an element.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

The element symbol : ZAX,Z (atomic number) = no. of protons. (protons = electrons)= 36.A (mass number) = no.of protons + no.of  neutrons.                           = 36 + 47 = 83.The symbol: 3683Kr.

The number of electron is equal to the number proton in the nucleus, thus the 36 electrons is same as 36 protons. The sum of protons and neutrons in the nucleus give the mass number of an element. The atomic number 36 indicates the element is Krypton. The represented symbol is 3683Kr.

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Chapter 2 Solutions

CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT

Ch. 2.5 - The average atomic mass of nitrogen is 14.0067....Ch. 2.5 - Prob. 2PPCCh. 2.5 - Boron has two naturally occurring isotopes, 10B...Ch. 2.5 - The two naturally occurring isotopes of antimony,...Ch. 2.6 - Prob. 2.6.1SRCh. 2.6 - Prob. 2.6.2SRCh. 2.7 - Calcium is the most abundant metal in the human...Ch. 2.7 - Prob. 3PPACh. 2.7 - Calculate (a) the number of atoms in 1.05 106...Ch. 2.7 - Prob. 3PPCCh. 2.7 - Prob. 2.4WECh. 2.7 - Prob. 4PPACh. 2.7 - Prob. 4PPBCh. 2.7 - Prob. 4PPCCh. 2.7 - Prob. 2.5WECh. 2.7 - Prob. 5PPACh. 2.7 - Prob. 5PPBCh. 2.7 - Prob. 5PPCCh. 2.7 - Prob. 2.7.1SRCh. 2.7 - Prob. 2.7.2SRCh. 2.7 - Prob. 2.7.3SRCh. 2.7 - Prob. 2.7.4SRCh. 2 - Define the terms atom and element.Ch. 2 - Use a familiar macroscopic example as an analogy...Ch. 2 - Prob. 2.3QPCh. 2 - Prob. 2.4QPCh. 2 - Prob. 2.5QPCh. 2 - Prob. 2.6QPCh. 2 - Describe the experimental basis for believing that...Ch. 2 - Prob. 2.8QPCh. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - Prob. 2.11QPCh. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Determine the mass number of (a) a beryllium atom...Ch. 2 - Prob. 2.21QPCh. 2 - The following radioactive isotopes are used in...Ch. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - What is the mass (in amu) of a carbon-12 atom? Why...Ch. 2 - Prob. 2.32QPCh. 2 - What information would you need to calculate the...Ch. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - The element rubidium has two naturally occurring...Ch. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Give two examples of each of the following: (a)...Ch. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Describe the changes in properties (from metals to...Ch. 2 - Consult the WebElements Periodic Table of the...Ch. 2 - Group the following elements in pairs that you...Ch. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.61QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - The element francium (Fr) was the last element of...Ch. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Discuss the significance of assigning an atomic...Ch. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - Prob. 2.76QPCh. 2 - Identify each of the following elements: (a) a...Ch. 2 - Prob. 2.78QPCh. 2 - Prob. 2.79QPCh. 2 - Prob. 2.80QPCh. 2 - Prob. 2.81QPCh. 2 - Prob. 2.82QPCh. 2 - Prob. 2.83QPCh. 2 - Prob. 2.84QP
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