   # Perform each of the following conversions within the metric system: a . 2319 cm to m b . 4912 .5 g to kg c . 23 .1 cm to mm d . 561 mL to L ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 2, Problem 26E
Textbook Problem
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## Perform each of the following conversions within the metric system: a . 2319 cm to m b . 4912 .5 g to kg c . 23 .1 cm to mm d . 561 mL to L

Interpretation Introduction

Interpretation:

Each of the given conversions within the metric system is to be performed.

Concept Introduction:

Dimensional analysis is useful in converting one unit to another.

To convert a quantity au1 from one unit to another, that is, u1u2, first write a conversion factor u2u1, then multiply the conversion factor with the given quantity au1, cancelling units to get the quantity in the desired unit as follows:

au1×u2u1=au2

### Explanation of Solution

a) 2319 cm to m.

To convert centimeter to m, first write the correct conversion factor by using the following relationship as:

1 m=100 cm

Thus, correct conversion factor will be (1 m100 cm).

Multiply the conversion factor with the given quantity, cancelling units to get the desired quantity.

Hence,

2319 cm×1 m100 cm=23.19 m

b) 4912.5 g to kg.

To convert gram to kg, first write the correct conversion factor by using the relationship as:

1 kg=1000 g

Thus, correct conversion factor will be (1 kg1000 g).

Multiply the conversion factor with the given quantity, cancelling units to get the desired quantity.

Hence,

4912.5 g×1 kg1000 g=4.9125 kg

c) 23

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