# f ( 3 ) , f ( 5 ) and f ( a − 1 ) ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 2, Problem 2T

a.

To determine

## To evaluate: f(3) , f(5) and f(a−1)

Expert Solution

f(3)=23 ; f(5)=65 and f(a1)=aa1

### Explanation of Solution

Given information: f(x)=x+1x

Concept used: To find the value of f(x) ; we evaluate the right hand side of the equation.

Calculation:

f(3)=3+13=43=23

f(5)=5+15=65=65

f(a1)=a1+1a1=aa1

b.

To determine

### To find: The domain of f

Expert Solution

The domain of f is x1  and   x0

### Explanation of Solution

Given information:

f(x)=x+1x

Concept Used:

Domain is a set of elements for which the function has a feasible value. The terms under square root cannot be negative.

Calculation:

f(x)=x+1x

(x+1) cannot be negative and x cannot be 0 as it is in denominator

(x+1)0x1

Since, 0 is not in domain of the function f ; the domain of f is x1  and   x0

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