To evaluate: , and
Concept used: To find the value of ; we evaluate the right hand side of the equation.
To find: The domain of
The domain of is
Domain is a set of elements for which the function has a feasible value. The terms under square root cannot be negative.
cannot be negative and cannot be as it is in denominator
Since, is not in domain of the function ; the domain of is
Subscribe to bartleby learn! Ask subject matter experts 30 homework questions each month. Plus, you’ll have access to millions of step-by-step textbook answers!