   Chapter 2, Problem 32P

Chapter
Section
Textbook Problem

An object moves with constant acceleration 4.00 m/s2 and over a time interval reaches a final velocity of 12.0 m/s. (a) If its original velocity is 6.00m/s, what is its displacement during the time interval? (b) What is the distance it travels during this interval? (c) If its original velocity is −6.00 m/s, what is its displacement during this interval? (d) What is the total distance it travels during the interval in part (c)?

(a)

To determine
The displacement of the object.

Explanation

Given Info: The initial velocity of the object is 6.00m/s , the final velocity of the object is 12.0m/s , and the acceleration of the object is 4.00m/s2 .

Explanation:

The formula used to calculate the displacement of the object is,

Δx=vf2vi22a

Here,

Δx is the displacement of the object

vf is the final velocity of the object

vi is the initial velocity of the object

a is the acceleration of the object

Substitute 6.00m/s for vi , 12

(b)

To determine
The distance travelled by the object.

(c)

To determine
The displacement of the object.

(d)

To determine
The distance travelled by the object.

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