Organic Chemistry
Organic Chemistry
3rd Edition
ISBN: 9781119338352
Author: Klein
Publisher: WILEY
Question
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Chapter 2, Problem 34PP
Interpretation Introduction

Interpretation:

All carbon atoms, hydrogen atoms and lone pairs can be drawn for the given bond-line structured compounds.

Concept introduction:

The representation of each atom with their symbol in a bond-line structure of a compound is called as the structural formula of that compound. In bond-line structure each corner represent the carbon atom which in bonded with hydrogen atoms. The number of hydrogen depends upon the number of atoms attached to that particular carbon, because the covalence of carbon should be four. The lone-pairs of the compound are the non-bonding valence electrons of hetero atoms occupied in the compound. It can be calculated by the formula,

Lonepairsofelectron=Valanceelectrons-Bondpairsofelectron2

Then the lone pairs are represented as dots on its heteroatoms in structural formula.

To draw: the all carbon atoms, hydrogen atoms and lone pairs for given compounds can be do with looking upon the corners of bond-line structure and attached heteroatoms.

Expert Solution & Answer
Check Mark

Answer to Problem 34PP

The structural formula of the following given compounds are

        Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  1                       Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  2      Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  3

Explanation of Solution

To draw all carbon atoms for given bond-line structures of compounds.

Put a carbon atom ‘C’ to each corner in bond-line structure.

Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  4Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  5Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  6

In bond-line structure, every corner represents the carbon atoms. Hence, all corners are replaced with the carbon symbol ‘C’.

To draw hydrogen atoms for given bond-line structure of compounds.

Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  7Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  8Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  9

Count the adjacent atoms of carbon whether it is carbon or heteroatoms and if it is less than four we have to add hydrogen atoms in that carbon to make four as covalence.

To draw lone pairs for compound structures.

Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  10Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  11

Organic Chemistry, Chapter 2, Problem 34PP , additional homework tip  12

In all given compounds the lone pairs of electron are carried by heteroatoms attached to the carbon. Hence, identify the heteroatoms presented in the compound and count its bond pairs of electrons. Because Lone pairs of electron are the non-bonding pairs of electrons. The numbers of lone pairs of electron are calculated by the formula,

Lonepairsofelectron=Valanceelectrons-Bondpairsofelectron2

These lone pairs are represented by dots on the atoms in structural formula.

Conclusion

The structural formula of given bond-line structured compounds are drawn by representing the all atoms presented in that compound and the number of lone pairs of electron are calculated by above equation.

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Chapter 2 Solutions

Organic Chemistry

Ch. 2.5 - Prob. 4LTSCh. 2.5 - Prob. 8PTSCh. 2.5 - The rich and varied flavors of toasted bread,...Ch. 2.5 - Prob. 5LTSCh. 2.5 - Prob. 10PTSCh. 2.5 - Prob. 11ATSCh. 2.8 - Prob. 6LTSCh. 2.8 - Prob. 12PTSCh. 2.8 - Prob. 13PTSCh. 2.8 - Prob. 14ATSCh. 2.9 - Prob. 7LTSCh. 2.9 - Prob. 15PTSCh. 2.9 - Prob. 16PTSCh. 2.9 - The cation 1 has been shown to lose a proton (H+)...Ch. 2.10 - Prob. 18CCCh. 2.10 - Prob. 19CCCh. 2.10 - Prob. 20CCCh. 2.10 - Prob. 21CCCh. 2.10 - Prob. 22CCCh. 2.10 - Prob. 23CCCh. 2.10 - Prob. 24CCCh. 2.10 - Prob. 25CCCh. 2.11 - Prob. 8LTSCh. 2.11 - Prob. 26PTSCh. 2.11 - Prob. 27ATSCh. 2.11 - Prob. 28ATSCh. 2.12 - Prob. 9LTSCh. 2.12 - Prob. 29PTSCh. 2.12 - The dragmacidin class of natural products has been...Ch. 2.13 - Prob. 10LTSCh. 2.13 - Prob. 31PTSCh. 2.13 - Prob. 32ATSCh. 2.13 - Prob. 33ATSCh. 2 - Prob. 34PPCh. 2 - Prob. 35PPCh. 2 - Prob. 36PPCh. 2 - Prob. 37PPCh. 2 - Prob. 38PPCh. 2 - Prob. 39PPCh. 2 - Prob. 40PPCh. 2 - Prob. 41PPCh. 2 - Prob. 42PPCh. 2 - Prob. 43PPCh. 2 - Prob. 44PPCh. 2 - Amino acids are biological compounds with the...Ch. 2 - Prob. 46PPCh. 2 - Prob. 47PPCh. 2 - Prob. 48PPCh. 2 - Prob. 49PPCh. 2 - Prob. 50PPCh. 2 - Prob. 51PPCh. 2 - Prob. 52PPCh. 2 - Prob. 53PPCh. 2 - Prob. 54PPCh. 2 - Prob. 55PPCh. 2 - Prob. 56PPCh. 2 - Prob. 57PPCh. 2 - Prob. 58PPCh. 2 - Prob. 59PPCh. 2 - Prob. 60PPCh. 2 - Prob. 61PPCh. 2 - Prob. 62PPCh. 2 - Enamines, compounds with an amino group attached...Ch. 2 - Prob. 64IPCh. 2 - Ramelteon is a hypnotic agent used in the...Ch. 2 - Prob. 66IPCh. 2 - Prob. 67IPCh. 2 - Prob. 68IPCh. 2 - The natural products 3 and 4 have similar core...Ch. 2 - Prob. 70IPCh. 2 - Prob. 71IPCh. 2 - Prob. 72IPCh. 2 - Prob. 73IPCh. 2 - Prob. 74IPCh. 2 - Prob. 75IPCh. 2 - Coumarin and its derivatives exhibit a broad array...Ch. 2 - Prob. 77IPCh. 2 - Prob. 78IPCh. 2 - Prob. 79IPCh. 2 - Prob. 80IPCh. 2 - Prob. 81CPCh. 2 - Prob. 82CPCh. 2 - Prob. 83CPCh. 2 - Prob. 84CP
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