   Chapter 2, Problem 39P

Chapter
Section
Textbook Problem

A car starts from rest and travels for 5.0 s with a uniform acceleration of +1.5 m/s2. The driver then applies the brakes, causing a uniform acceleration of −2.0 m/s2. If the brakes are applied for 3.0 s, (a) how fast is the car going at the end of the braking period, and (b) how far has the car gone?

(a)

To determine
The velocity of the car.

Explanation

Given Info: The initial velocity of the car is 0 , the first time interval is 5.0s , The acceleration in first interval 1.5m/s2 , the second time interval is 3.0s , and the acceleration in second interval 2.0m/s2 .

Explanation:

The formula used to calculate the final velocity of the car in first interval is,

v=v0+at

Here,

t is the first interval

v is the final velocity of the car in first interval

v0 is the initial velocity of the car in first interval

a is the acceleration of the car in first interval

Substitute 0 for v0 , 1.5m/s2 for a , and 5.0s for t to find v .

v=0+(1.5m/s2)(5.0s)=7

(b)

To determine
The distance travelled by the car.

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