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A thief plans to steal a bar of gold from a woman’s purse and replace it with a bag of sand. Assume that the volumes of the gold and the sand are 350 mL each and that the density of sand is 3 .00 g/cm 3 . a. Calculate the mass of each object. b. Would the woman notice a difference in the weight of her purse?

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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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Chapter
Section
BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 2, Problem 44E
Textbook Problem

A thief plans to steal a bar of gold from a woman’s purse and replace it with a bag of sand. Assume that the volumes of the gold and the sand are 350 mL each and that the density of sand is 3 .00 g/cm 3 .

a. Calculate the mass of each object.

b. Would the woman notice a difference in the weight of her purse?

Interpretation Introduction

Interpretation:

The mass of gold and sand is to be calculated and whether the woman will notice the difference in the weight of her purse is to be predicted.

Concept Introduction:

Density of a substance is a measure of compactness of that substance. It is defined as the mass of a substance present in per unit of its volume. The unit of density is derived when the unit of mass is divided by the unit of volume. Its most common units are g/cm3 and g/mL.

Density = Mass Volume

It is known that 1mL = 1 cm3, conversion factor is as:

1 cm31mL

Explanation of Solution

a) Mass of sand and gold

The mass of sand and gold is calculated as follows:

Calculation of mass of sand is as follows:

Density of sand = Mass of sandVolume of sand 

The density of sand is 3.00 g/cm3.

Substitute the values in the above equation as:

mass of sand=350mL×1cm31mL×3.00 g1 cm3mass of sand=1.0×103 g

Hence, the mass of sand is 1.0×103 g.

The calculation of mass of gold is as:

Taking, density of gold = 19

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Chemistry In Focus
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