   Chapter 2, Problem 46P

Chapter
Section
Textbook Problem

A ball is thrown directly downward with an initial speed of 8.00 m/s, from a height of 30.0 m. After what time interval does it strike the ground?

To determine
The taken by the ball to hit the ground.

Explanation

Given Info: The initial velocity of the ball is 8.00m/s , the acceleration of the ball is 9.80m/s2 , and the displacement of the ball is 30.0m .

Explanation:

The formula used to calculate the final velocity of the ball is,

vy=v0y2+2ay(Δy)

Here

Δy is the displacement of the ball

vy is the final velocity of the ball

v0y is the initial velocity of the ball

ay is the acceleration of the ball

Substitute 8.00m/s for v0y , 9.80m/s2 for ay , and 30.0m for Δy to find vy .

vy=(8.00m/s)2+2(9.80m/s2)(30

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