   Chapter 2, Problem 57AP

Chapter
Section
Textbook Problem

A bullet is fired through a board 10.0 cm thick in such a way that the bullet’s line of motion is perpendicular to the face of the board. If the initial speed of the bullet is 4.00 × 102 m/s and it emerges from the other side of the board with a speed of 3.00 × 102 m/s, find (a) the acceleration of the bullet as it passes through the board and (b) the total time the bullet is in contact with the board.

(a)

To determine
The acceleration of the bullet.

Explanation

Given Info: The initial velocity of the bullet is 400m/s , the final velocity of the bullet is 300m/s , and the displacement of the bullet is 0.100m .

Explanation:

The formula used to calculate the acceleration of the bullet is,

a=v2v022Δx

Here,

v is the final velocity of the bullet

v0 is the initial velocity of the bullet

a is the acceleration of the bullet

Δx is the displacement of the bullet

Substitute 400m/s for v0 , 300m/s for v and 0.100m for Δx to find a

(b)

To determine
The time of contact of the bullet with the board.

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