   Chapter 2, Problem 59AP

Chapter
Section
Textbook Problem

A student throws a set of keys vertically upward to his fraternity brother, who is in a window 4.00 m above. The brother's outstretched hand catches the keys 1.50 s later. (a) With what initial velocity were the keys thrown? (b)? What was the velocity of the keys just before they were caught?

(a)

To determine
The initial velocity of the keys.

Explanation

Given Info: The time taken by the key to reach the maximum height is 1.50s , the acceleration of the keys is 9.80m/s2 , and the displacement of the keys is 4.00m .

Explanation:

The formula used to calculate the displacement of the keys is,

Δx=v0t+12at2

Here,

Δx is the displacement of the keys

t is time took by the keys to reach the maximum height

v0 is the initial velocity of the keys

a is the acceleration

Rearrange the equation to calculate the initial velocity of the keys. The formula used to calculate the initial velocity of the keys is,

v0=Δxt12at

Substitute 4.00m for Δx , 9

(b)

To determine
The velocity of the keys just before the catch.

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