# To find the annual amount (in dollars) deposited using the given function D ( t ) = 3500 + 15 t 2 for t = 0 and t=15 .

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 2, Problem 60RE

a.

To determine

## To find the annual amount (in dollars) deposited using the given function D(t)=3500+15t2for t=0 and t=15.

Expert Solution

The annual amount (in dollars) deposited using the given function D(t)=3500+15t2for t=0 and t=15is D(0)=3500 and D(15)=6875.

### Explanation of Solution

Given information: Consider the function, D(t)=3500+15t2

Calculation: Substitute t=0 and t=15,

D(0)=3500+15(0)2        =3500Now,D(15)=3500+15(15)2=3500+15(225)=3500+3375=6875

D(15) is 6875

In 1995 Ella has deposited 3500 dollars and in 2010 she got back 6875 dollars.

is what the value of represents.

b.

To determine

### Explanation of Solution

Given information: Consider the function, D(t)=3500+15t2

Calculation:

The given function,

D(t)=1700017000=3500+15(t)2or,15(t)2=17000350015(t)2=13500(t)2=1350015(t)2=900t=30

### Explanation of Solution

Given information: Consider the function, D(t)=3500+15t2

Calculation:

Since in Ella deposited $3500 (when t=0 ) and she got back$6875 $6875 (when t=15 ). So, the difference in 15 years is calculated as, 68753500=3375 Now the average rate of change of D between t=0t=15337515=225 Hence,$225 per year is the average rate of change and this represents average annual increase.

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