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Chapter 2, Problem 63AP
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### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

#### Solutions

Chapter
Section
BuyFindarrow_forward

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# A ball is thrown upward from the ground with an initial speed of 25 m/s; at the same instant, another ball is dropped from a building 15 m high. After how long will the balls be at the same height?

To determine
The time taken to the ball to reach the same height.

Explanation

Given Info: The initial velocity of the first ball is 25.0â€‰m/s and the initial position of the second ball is 15.0â€‰m

Explanation:

The formula used to calculate the position of the first ball is,

h=v0tâˆ’12gt2 (1)

Here,

h is the position at which the balls meet

v0 is the initial velocity of the first ball

a is the acceleration of the first ball

t is the time at which the balls meet

The formula used to calculate the position of the second ball is,

h=h0âˆ’12gt2 (2)

Here,

h0 is the position of the second ball

Compare the equations (1) and (2) for position of the balls.

v0tâˆ’12gt2=h0âˆ’12gt2

Rearrange the equation to calculate the time at which the balls meet

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