   # A semiconducting material is composed of 52 g of Ga, 9.5 g of Al, and 112 g of As. Which element has the largest number of atoms in this material? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 2, Problem 68PS
Textbook Problem
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## A semiconducting material is composed of 52 g of Ga, 9.5 g of Al, and 112 g of As. Which element has the largest number of atoms in this material?

Interpretation Introduction

Interpretation:

The elements in given semiconductor sample is needed to be arranged in the order of smallest to largest in numbers of atoms.

Concept introduction:

Molar masses of Ga, Al, and As are 69.7g, 26.9g and 74.9 respectively.

• Conversion formula for mass of an atom into number moles,

Numberofmoles=MassingramsMolarmass

• Equation for finding number of atoms from number of moles of an atom,

Numberofatoms=numberofmolesofatom×6.022×1023atoms/mol

### Explanation of Solution

Conversion formula for mass of an atom into number moles,

Numberofmoles=MassingramsMolarmass

The masses of elements in the sample are different. Masses of Ga, Al and As in sample are 52g, 9.5g and 112g respectively.

Therefore,

The number of moles gallium is,

Numberofmoles=5269.7=0.746mol

The number of moles aluminum is,

Numberofmoles=9.526.9=0.353mol

The number of moles arsenic is,

Numberofmoles=11274

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