# Find the maximum value of the function is h ( x ) = − 16 t 2 + 48 t + 32

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 2, Problem 69RE
To determine

## Find the maximum value of the function is h(x)=−16t2+48t+32

Expert Solution

The maximum value of h(x)=16t2+48t+32 is 68feet

### Explanation of Solution

Given information: Consider the function is h(x)=16t2+48t+32

Calculation:

This is quadratic equation with a=16,b=48

Thus, the maximum or minimum value occurs at

x=b2a=482×(16)=4832=32

Since a>0 , the function has the maximum value

h(32)=16(32)2+48(32)+32=16×94+48(32)+32=36+72+32=68

Thus, the maximum value of h(x)=16t2+48t+32 is 68feet

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