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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

How many ammonium ions and how many sulfate ions are present in a 0.20 mol sample of (NH4)2SO4? How many atoms of N, H, S and O are contained in this sample?

Interpretation Introduction

Interpretation:

For the given sample of ammonium sulfate, the number of moles of ammonium ions and sulfate ions, the numbers of N, H, S and O-atoms are needed to be calculated.

Concept introduction:

Ionic compound are constituted by cations and anions.

  • Equation for finding number of atoms from number of moles of a molecule,

Numberofatoms=numberofmolesofatoms×6.022×1023atoms/mol

Explanation

The amount of ammonium sulfate is given as 0.20mol.

Ammonium sulfate is composed of ammonium ion and sulfate ions.

That is, two ammonium ions and one sulfate ion per ammonium sulfate compound.

Therefore,

The number of moles of ammonium ion is 2×0.20mol=0.40mol

The number of moles of ammonium ion is 0.20mol

Equation for finding number of atoms from number of moles of a molecule,

Numberofatoms=numberofmolesofatoms×6.022×1023atoms/mol

Therefore,

There are 2nitrogen atoms, 8hydrogen atoms, 1sulfur atom and 4oxygen atoms per ammonium sulfate, so the number of N, H, S and O atoms in given sample of ammonium sulfate (0.20 mol) is,

    NumberofNatoms=0.20mol×2×6.022×1023atoms/mol=2.4×1023Natoms

    NumberofHatoms=0

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