   Chapter 2, Problem 90PS

Chapter
Section
Textbook Problem

In 2006, a Russian team discovered an interesting molecule they called “sulflower” because of its shape and because it was based on sulfur. It is composed of 57.17% S and 42.83% C and has a molar mass of 448.70 g/mol. Determine the empirical and molecular formulas of “sulflower.”

Interpretation Introduction

Interpretation:

The empirical formula and molecular formula of the sulflower is to be determined if the molar mass is 448.7g/mol

Concept introduction:

• Empirical formula of a compound represents the smallest whole number relative ratio of elements in that compound.
• Equation for finding Molecular formula from the empirical formula,

MolarmassEmpiricalformula mass × Empirical formula

• Equation for number moles from mass and molar mass,

Numberofmoles=MassingramsMolarmass

• Mass percent of elements of a compound is the ratio of mass of element to the mass of whole compound and multiplied with hundred.
Explanation

Mass percent of sulfur, and carbon in sulflower is given as 57.17% and 42.83%.

Mass percent of an element means, 100g of compound contains that mass percent of an element in grams. Therefore, mass of sulfur and carbon are 57.17g and 42.83g respectively in 100g of sulflower.

Equation for number moles from mass and molar mass is,

Numberofmoles=MassingramsMolarmass

Therefore,

The number of moles of carbon is,

Numberofmoles=42.83g12.01g/mol=3.56mol

The number of moles of sulfur is,

Numberofmoles=57

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