General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN: 9781305580343
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher: Cengage Learning
Question
Chapter 20, Problem 20.107QP

(a)

Interpretation Introduction

Interpretation:

Given reaction has to be completed.

(a)

Expert Solution
Check Mark

Answer to Problem 20.107QP

Completed equation is,

1431Si1531P + -10e

Explanation of Solution

Given incomplete nuclear reaction is,

1431Si1531P + ?

This is written as,

1431Si1531P + ZAX

Where, Z is atomic number A is mass number.

From superscripts:  31+A = 31A = 0From subscripts:    15+Z = 14Z = -1

So, the missing particle in the reaction is -10X , which is identified as an electron.  The symbol of electron is -10e .  Thus the reaction is written as,

1431Si1531P + -10e

(b)

Interpretation Introduction

Interpretation:

Given reaction has to be completed.

(b)

Expert Solution
Check Mark

Answer to Problem 20.107QP

Completed reactions are,

2244Ti + -10e2144Sc

Explanation of Solution

Given incomplete nuclear reaction is,

2244Ti + ?2144Sc

This is written as,

2244Ti + ZAX2144Sc

Where, Z is atomic number A is mass number.

From superscripts:  44+A = 44A = 0From subscripts:    22+Z = 21Z = -1

So, the missing particle in the reaction is -10X , which is identified as an electron.  The symbol of electron is -10e .  Thus the reaction is written as,

2244Ti + -10e2144Sc

(c)

Interpretation Introduction

Interpretation:

Given reaction has to be completed.

(c)

Expert Solution
Check Mark

Answer to Problem 20.107QP

Completed reactions are,

98252Cf  56142Ba42106Mo + 401n

Explanation of Solution

Given incomplete nuclear reaction is,

98252Cf  56142Ba+ ? + 401n

This is written as,

98252Cf  56142BaZAX + 401n

Where, Z is atomic number A is mass number.

From superscripts:  142+A +4(1)=252A = 106From subscripts:    56+Z = 98Z = 42

The atomic number is 42 and mass number is 106.  So, the missing element in the reaction is 42106X .  The element with atomic number of 42 and mass number of 106 is found to be Molybdenum.  The nuclide symbol of Molybdenum is 42106Mo .  Thus the reaction is written as,

98252Cf  56142Ba42106Mo + 401n

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Chapter 20 Solutions

General Chemistry - Standalone book (MindTap Course List)

Ch. 20.4 - Prob. 20.9ECh. 20.4 - Prob. 20.10ECh. 20.4 - Prob. 20.11ECh. 20.4 - Prob. 20.3CCCh. 20.6 - Prob. 20.12ECh. 20 - Prob. 20.1QPCh. 20 - Prob. 20.2QPCh. 20 - Prob. 20.3QPCh. 20 - Prob. 20.4QPCh. 20 - Prob. 20.5QPCh. 20 - Prob. 20.6QPCh. 20 - Prob. 20.7QPCh. 20 - Prob. 20.8QPCh. 20 - Prob. 20.9QPCh. 20 - Prob. 20.10QPCh. 20 - Prob. 20.11QPCh. 20 - Prob. 20.12QPCh. 20 - Prob. 20.13QPCh. 20 - Prob. 20.14QPCh. 20 - Prob. 20.15QPCh. 20 - Prob. 20.16QPCh. 20 - Prob. 20.17QPCh. 20 - Prob. 20.18QPCh. 20 - Prob. 20.19QPCh. 20 - Prob. 20.20QPCh. 20 - Prob. 20.21QPCh. 20 - Prob. 20.22QPCh. 20 - Prob. 20.23QPCh. 20 - Prob. 20.24QPCh. 20 - Prob. 20.25QPCh. 20 - Prob. 20.26QPCh. 20 - Prob. 20.27QPCh. 20 - Prob. 20.28QPCh. 20 - Prob. 20.29QPCh. 20 - Prob. 20.30QPCh. 20 - Prob. 20.31QPCh. 20 - Prob. 20.32QPCh. 20 - Prob. 20.33QPCh. 20 - Prob. 20.34QPCh. 20 - Prob. 20.35QPCh. 20 - Prob. 20.36QPCh. 20 - Prob. 20.37QPCh. 20 - Prob. 20.38QPCh. 20 - Prob. 20.39QPCh. 20 - Prob. 20.40QPCh. 20 - Prob. 20.41QPCh. 20 - Prob. 20.42QPCh. 20 - Prob. 20.43QPCh. 20 - Prob. 20.44QPCh. 20 - Prob. 20.45QPCh. 20 - Prob. 20.46QPCh. 20 - Prob. 20.47QPCh. 20 - Prob. 20.48QPCh. 20 - Prob. 20.49QPCh. 20 - Prob. 20.50QPCh. 20 - Prob. 20.51QPCh. 20 - Prob. 20.52QPCh. 20 - Fill in the missing parts of the following...Ch. 20 - Fill in the missing parts of the following...Ch. 20 - Prob. 20.55QPCh. 20 - Prob. 20.56QPCh. 20 - Prob. 20.57QPCh. 20 - Prob. 20.58QPCh. 20 - Prob. 20.59QPCh. 20 - Prob. 20.60QPCh. 20 - Prob. 20.61QPCh. 20 - Prob. 20.62QPCh. 20 - Prob. 20.63QPCh. 20 - Prob. 20.64QPCh. 20 - Prob. 20.65QPCh. 20 - Prob. 20.66QPCh. 20 - Prob. 20.67QPCh. 20 - Prob. 20.68QPCh. 20 - Prob. 20.69QPCh. 20 - Prob. 20.70QPCh. 20 - Prob. 20.71QPCh. 20 - Prob. 20.72QPCh. 20 - Prob. 20.73QPCh. 20 - Prob. 20.74QPCh. 20 - Prob. 20.75QPCh. 20 - Prob. 20.76QPCh. 20 - Prob. 20.77QPCh. 20 - Prob. 20.78QPCh. 20 - Find the change of mass (in grams) resulting from...Ch. 20 - Find the change of mass (in grams) resulting from...Ch. 20 - Prob. 20.81QPCh. 20 - Prob. 20.82QPCh. 20 - Prob. 20.83QPCh. 20 - Prob. 20.84QPCh. 20 - Prob. 20.85QPCh. 20 - Prob. 20.86QPCh. 20 - Prob. 20.87QPCh. 20 - Prob. 20.88QPCh. 20 - Prob. 20.89QPCh. 20 - Prob. 20.90QPCh. 20 - Prob. 20.91QPCh. 20 - Prob. 20.92QPCh. 20 - Prob. 20.93QPCh. 20 - Prob. 20.94QPCh. 20 - Prob. 20.95QPCh. 20 - Prob. 20.96QPCh. 20 - Prob. 20.97QPCh. 20 - Prob. 20.98QPCh. 20 - Prob. 20.99QPCh. 20 - Prob. 20.100QPCh. 20 - Prob. 20.101QPCh. 20 - Prob. 20.102QPCh. 20 - Prob. 20.103QPCh. 20 - Prob. 20.104QPCh. 20 - Prob. 20.105QPCh. 20 - Prob. 20.106QPCh. 20 - Prob. 20.107QPCh. 20 - Prob. 20.108QPCh. 20 - Prob. 20.109QPCh. 20 - Prob. 20.110QPCh. 20 - Prob. 20.111QPCh. 20 - Prob. 20.112QPCh. 20 - Prob. 20.113QPCh. 20 - Prob. 20.114QPCh. 20 - Prob. 20.115QPCh. 20 - Prob. 20.116QPCh. 20 - Prob. 20.117QPCh. 20 - Prob. 20.118QPCh. 20 - Prob. 20.119QPCh. 20 - Prob. 20.120QPCh. 20 - Prob. 20.121QPCh. 20 - Prob. 20.122QPCh. 20 - Prob. 20.123QPCh. 20 - Prob. 20.124QPCh. 20 - Prob. 20.125QPCh. 20 - Prob. 20.126QPCh. 20 - Prob. 20.127QPCh. 20 - Prob. 20.128QP
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