Applied Statics and Strength of Materials (6th Edition)
Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Question
Chapter 20, Problem 20.1P
To determine

Circumferential stress developed in the walls of the pipe.

Expert Solution & Answer
Check Mark

Answer to Problem 20.1P

   Stc=14953.84psi

Explanation of Solution

Given:

Diameter of water pipe Di=9ft

Wall thickness of steel plate t=1316in=0.8125in

Internal pressure of water in the pipe p=225psi

Calculation:

Thin wall theory is applicable if t0.1ri

   0.1ri=0.1( 9×122)inri=5.4in0.8125in<5.4in(OK)

From the above values, the condition for thin wall theory is satisfied, therefore, the circumferential stress developed in the walls of the pipe is calculated by the formula:

   Stc=pDi2tStc=225×( 9×12)2( 0.8125)Stc=14953.84psi

Conclusion:

Therefore, circumferential stress developed in the walls of the pipe is = 14953.84psi.

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