CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
14th Edition
ISBN: 9781259327933
Author: Burdge
Publisher: MCG
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Question
Chapter 20, Problem 20.65QP
Interpretation Introduction

Interpretation: For the given nuclear reaction, X should be identified and the equation should be balanced.

Concept Introduction:

  • Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted particle that is ejectile which can be represented as the second particle in the parentheses.

Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively.

7N15(p,α)6C12Parentnucleus(Projectile,ejectile)Daughternucleus

  • On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal.

To find: The value of X in the given nuclear equation (a).

Expert Solution & Answer
Check Mark

Answer to Problem 20.65QP

(a)       U92235+n01Ba56140+3n01+Kr3693_              X=Kr3693_(b)       U92235+n01Cs55144+Rb3790+2n01_             X=2n01_(c)       U92235+n01Br3587+La57146_+3n01            X=La57146_(d)      U92235+n01Sm62160+Zn3072+4n01_            X=4n01_

X=Kr3693_

Explanation of Solution

Explanation

Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted particle that is ejectile which can be represented as the second particle in the parentheses. Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively. So for any nuclear reaction, short hand notation will be in this form that is, Parentnucleus(Projectile,ejectile)Daughternucleus

For the given reaction a, Short hand notation is U92235(n,n)X . From the notation it is clear that,

CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT, Chapter 20, Problem 20.65QP

The given chemical equation can be written as,

U92235+n01Ba56140+3n01+ X

On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal. So the X will be 3693X . By analyzing the X, atomic number of X is 36 and the atomic mass is 93. So it is found that X is Kr3693 .

 So the balanced equation can be written as,

U92235+n01Ba56140+3n01+Kr3693_

Find the value of X in the given nuclear equation (b)

X=2n01_

For the given reaction b, Shorthand notation is U92235(n01,Cs55144)X . From the notation it is clear that,

Parentnucleus-U92235Projectile-n10Daughternucleus-Cs55144Ejectile-X

The given chemical equation can be written as,

U92235+n01Cs55144+Rb3790+ X

On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal. So the X will be 012X . By analyzing the X, atomic number of X is 0 and the atomic mass is 1. It is found that X=2n01_ .

 So the balanced equation can be written as,

U92235+n01Cs55144+Rb3790+2n01_

Find the value of X in the given nuclear equation (c).

For the given reactions, Shorthand notation is U92235(n,n)X . From the notation it is clear that,

Parentnucleus-U92235Projectile10nDaughternucleus-XEjectile-10n

The given chemical equation can be written as,

U92235+n01Br3587+ X+ 3n01

On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal. So X will be 57146X . By analyzing the X, atomic number of X is57 and the atomic mass is 146. So it should be the isotope of lanthanum. It is found that X=La57146_

 So the balanced equation can be written as,

U92235+n01Br3587+La57146_+3n01

Find the value of X in the given nuclear equation (d).

For the given reactions, Shorthand notation is U92235(n,n)X . From the notation it is clear that,

Parentnucleus-U92235Projectile10nDaughternucleus-XEjectile-10n

The given chemical equation can be written as,

U92235+n01Sm62160+Zn3072+ X

On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal. So X will be 014X . By analyzing the X, atomic number of X is0 and the atomic mass is 1. It is found that X=4n01_

 So the balanced equation can be written as,

U92235+n01Sm62160+Zn3072+4n01_

Conclusion

For the given nuclear reaction, X is identified and the equation is balanced.

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Chapter 20 Solutions

CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT

Ch. 20.2 - Prob. 20.2.1SRCh. 20.2 - Prob. 20.2.2SRCh. 20.2 - Prob. 20.2.3SRCh. 20.2 - Prob. 20.2.4SRCh. 20.3 - Prob. 20.3WECh. 20.3 - Prob. 3PPACh. 20.3 - Prob. 3PPBCh. 20.3 - Prob. 3PPCCh. 20.3 - Prob. 20.4WECh. 20.3 - Prob. 4PPACh. 20.3 - Prob. 4PPBCh. 20.3 - Prob. 4PPCCh. 20.3 - Prob. 20.3.1SRCh. 20.3 - Prob. 20.3.2SRCh. 20.3 - Prob. 20.3.3SRCh. 20.4 - Prob. 20.5WECh. 20.4 - Prob. 5PPACh. 20.4 - Prob. 5PPBCh. 20.4 - Prob. 5PPCCh. 20.4 - Prob. 20.4.1SRCh. 20.4 - Prob. 20.4.2SRCh. 20 - Prob. 20.1QPCh. 20 - Prob. 20.2QPCh. 20 - Prob. 20.3QPCh. 20 - Prob. 20.4QPCh. 20 - Prob. 20.5QPCh. 20 - Prob. 20.6QPCh. 20 - Prob. 20.7QPCh. 20 - Prob. 20.8QPCh. 20 - Prob. 20.9QPCh. 20 - Prob. 20.10QPCh. 20 - Prob. 20.11QPCh. 20 - Prob. 20.12QPCh. 20 - Prob. 20.13QPCh. 20 - Prob. 20.14QPCh. 20 - Prob. 20.15QPCh. 20 - Prob. 20.16QPCh. 20 - Prob. 20.17QPCh. 20 - Prob. 20.18QPCh. 20 - Prob. 20.19QPCh. 20 - Prob. 20.20QPCh. 20 - Prob. 20.21QPCh. 20 - Prob. 20.22QPCh. 20 - Prob. 20.23QPCh. 20 - Prob. 20.24QPCh. 20 - Prob. 20.25QPCh. 20 - Prob. 20.26QPCh. 20 - Prob. 20.27QPCh. 20 - Prob. 20.28QPCh. 20 - Prob. 20.29QPCh. 20 - Prob. 20.30QPCh. 20 - Prob. 20.31QPCh. 20 - Prob. 20.32QPCh. 20 - Prob. 20.33QPCh. 20 - Prob. 20.34QPCh. 20 - Prob. 20.35QPCh. 20 - Prob. 20.36QPCh. 20 - Prob. 20.37QPCh. 20 - Prob. 20.38QPCh. 20 - Prob. 20.39QPCh. 20 - Prob. 20.1VCCh. 20 - Prob. 20.2VCCh. 20 - Prob. 20.3VCCh. 20 - Prob. 20.4VCCh. 20 - Prob. 20.40QPCh. 20 - Prob. 20.41QPCh. 20 - Prob. 20.42QPCh. 20 - Prob. 20.43QPCh. 20 - Prob. 20.44QPCh. 20 - Prob. 20.45QPCh. 20 - Prob. 20.46QPCh. 20 - Prob. 20.47QPCh. 20 - Prob. 20.48QPCh. 20 - Prob. 20.49QPCh. 20 - Prob. 20.50QPCh. 20 - Prob. 20.51QPCh. 20 - Prob. 20.52QPCh. 20 - Prob. 20.53QPCh. 20 - Prob. 20.54QPCh. 20 - Prob. 20.55QPCh. 20 - Prob. 20.56QPCh. 20 - Prob. 20.57QPCh. 20 - Prob. 20.58QPCh. 20 - Prob. 20.59QPCh. 20 - Prob. 20.60QPCh. 20 - Prob. 20.61QPCh. 20 - Prob. 20.62QPCh. 20 - Prob. 20.63QPCh. 20 - Prob. 20.64QPCh. 20 - Prob. 20.65QPCh. 20 - Prob. 20.66QPCh. 20 - Prob. 20.67QPCh. 20 - Prob. 20.68QPCh. 20 - Prob. 20.69QPCh. 20 - Prob. 20.70QPCh. 20 - Prob. 20.71QPCh. 20 - Prob. 20.72QPCh. 20 - Prob. 20.73QPCh. 20 - Prob. 20.74QPCh. 20 - Prob. 20.75QPCh. 20 - Prob. 20.76QPCh. 20 - Prob. 20.77QPCh. 20 - Prob. 20.78QPCh. 20 - Prob. 20.79QPCh. 20 - Prob. 20.80QPCh. 20 - Prob. 20.81QPCh. 20 - Prob. 20.82QPCh. 20 - Prob. 20.83QPCh. 20 - Prob. 20.84QPCh. 20 - Prob. 20.85QPCh. 20 - Prob. 20.86QPCh. 20 - Prob. 20.87QPCh. 20 - Prob. 20.88QPCh. 20 - Prob. 20.89QPCh. 20 - Prob. 20.90QPCh. 20 - Prob. 20.91QPCh. 20 - Prob. 20.92QPCh. 20 - Prob. 20.93QPCh. 20 - Prob. 20.94QPCh. 20 - Prob. 20.95QPCh. 20 - Prob. 20.96QPCh. 20 - Prob. 20.97QPCh. 20 - Prob. 20.98QPCh. 20 - Prob. 20.99QPCh. 20 - Prob. 20.100QPCh. 20 - Prob. 20.101QP
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