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Chemistry: Atoms First

3rd Edition
Julia Burdge + 1 other
ISBN: 9781259638138

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry: Atoms First

3rd Edition
Julia Burdge + 1 other
ISBN: 9781259638138

(a)

Interpretation Introduction

Interpretation: The total energy released by the quantity of 84210Po over the course of 138 days should be calculated& the equation should be drawn for the both cases (a)& (b).

Concept Introduction

  • Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted particle that is ejectile which can be represented as the second particle in the parentheses.

Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively.

           7N15(p,α)6C12Parentnucleus(Projectile,ejectile)Daughternucleus

  • On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal.

To calculate the nuclear binding energy.:

  • Firstly determine the difference between the mass of the nucleus and the mass of all the protons and neutrons, which yields the mass defect.
  • Next, we must apply Einstein mass – energy relationship.
  • The nuclear binding energy per nucleon is given by the following equation:
  • Nuclear binding energy per nucleus= nuclear binding energynumber of nucleons
  • Einstein mass energy relationship [ ΔE=(ΔM)c2 ].

(b)

Interpretation Introduction

Interpretation: The total energy released by the quantity of 84210Po over the course of 138 days should be calculated& the equation should be drawn for the both cases (a)& (b).

Concept Introduction

  • Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted particle that is ejectile which can be represented as the second particle in the parentheses.

Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively.

           7N15(p,α)6C12Parentnucleus(Projectile,ejectile)Daughternucleus

  • On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal.

To calculate the nuclear binding energy.:

  • Firstly determine the difference between the mass of the nucleus and the mass of all the protons and neutrons, which yields the mass defect.
  • Next, we must apply Einstein mass – energy relationship.
  • The nuclear binding energy per nucleon is given by the following equation:
  • Nuclear binding energy per nucleus= nuclear binding energynumber of nucleons
  • Einstein mass energy relationship [ ΔE=(ΔM)c2 ].

(c)

Interpretation Introduction

Interpretation: The total energy released by the quantity of 84210Po over the course of 138 days should be calculated& the equation should be drawn for the both cases (a)& (b).

Concept Introduction

  • Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted particle that is ejectile which can be represented as the second particle in the parentheses.

Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively.

           7N15(p,α)6C12Parentnucleus(Projectile,ejectile)Daughternucleus

  • On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal.

To calculate the nuclear binding energy.:

  • Firstly determine the difference between the mass of the nucleus and the mass of all the protons and neutrons, which yields the mass defect.
  • Next, we must apply Einstein mass – energy relationship.
  • The nuclear binding energy per nucleon is given by the following equation:
  • Nuclear binding energy per nucleus= nuclear binding energynumber of nucleons
  • Einstein mass energy relationship [ ΔE=(ΔM)c2 ].

To identify:  The energy of an emitting alpha particle

(d)

Interpretation Introduction

Interpretation: The total energy released by the quantity of 84210Po over the course of 138 days should be calculated& the equation should be drawn for the both cases (a)& (b).

Concept Introduction

  • Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted particle that is ejectile which can be represented as the second particle in the parentheses.

Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively.

           7N15(p,α)6C12Parentnucleus(Projectile,ejectile)Daughternucleus

  • On accordance with law of conservation of mass, for any chemical reaction, total masses of reactants and products must be equal.

To calculate the nuclear binding energy.:

  • Firstly determine the difference between the mass of the nucleus and the mass of all the protons and neutrons, which yields the mass defect.
  • Next, we must apply Einstein mass – energy relationship.
  • The nuclear binding energy per nucleon is given by the following equation:
  • Nuclear binding energy per nucleus= nuclear binding energynumber of nucleons
  • Einstein mass energy relationship [ ΔE=(ΔM)c2 ].

To identify:  The number of polonium atoms in 1 μ g:

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