   Chapter 20, Problem 20E

Chapter
Section
Textbook Problem

# Write balanced equations describing the reaction of Sr with each of the following: O2, S, Cl2, P4, H2, H2O, and HCl.

Interpretation Introduction

Interpretation: The balanced equations to describe the reaction of Sr with each O2,S,Cl2,P4,H2,H2O and HCl are to be stated.

Concept introduction: Strontium (Sr) is an alkaline earth metal which is found in group 2A in the periodic table. Alkaline earth metals are highly reactive and form ionic compound by losing two valence electrons and contain M2+ cation.

To determine: The balanced equations to describe the reaction of Sr with each O2,S,Cl2,P4,H2,H2O and HCl .

Explanation

Explanation

The balanced equations to describe the reaction of Sr with each O2,S,Cl2,P4,H2,H2O and HCl is,

Reaction of Sr with oxygen (O2) yields strontium oxide (SrO) . The reaction is,

2Sr(s)+O2(g)2SrO(s)

Reaction of Sr with sulfur (S) yields strontium sulfide (SrS) . The reaction is,

Sr(s)+S(s)SrS(s)

Reaction of Sr with chlorine (Cl2) yields strontium (II) chloride (SrCl2) . The reaction is,

Sr(s)+Cl2(g)SrCl2(s)

Reaction of Sr with phosphorous (P4) yields strontium phosphide (Sr3P2) . The reaction is,

6Sr(s)+P4(s)2Sr3P2(s)

Reaction of Sr with hydrogen (H2) yields strontium hydride (SrH2)

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