A solenoid with 505 turns has a length of 7.00 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +4.00 A to −4.00 A in 7.83 ✕ 10−3 s.   (a) the solenoid's inductance (in H)     (b) the average emf around the solenoid (in V)

Q: A solenoid with 435 turns has a length of 7.50 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find…

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Q: A solenoid with 485 turns has a length of 7.00 cm and a cross-sectional area of 3.50 x 10-9 m2. Find…

A: a) The inductance of the solenoid can be obtained as L=μ∘N2AlSubstituting the given values :L=(4π x…

Q: A circuit is constructed with four resistors, one inductor, one battery and a switch as shown. The…

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Q: 6.0 μsμs after the switch of (Figure 1) is moved from 1 to 2, the magnetic energy stored in the…

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Q: A solenoid with 455 turns has a length of 8.00 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find…

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Q: h y L Calaulate the inductance of the very long conductive wire that carries current I and the…

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Q: Two coils close to each other have a mutual inductance of 32 mH. If the current in one coil decays…

A: The expression for the EMF of a coil, ε=-dϕdtThe magnetic flux of the coil isϕ=MI

Q: A 5.70 x 10 -5 H solenoid is constructed by wrapping 80 turns of wire around a cylinder with a…

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Q: What is the self-inductance of an ideal solenoid that is 300 cm long with a cross-sectional area of…

A: Length (L) = 300 cm  = 3 m  Area of cross section (A) = 10-4 m2  Number of turns (N) = 1000

Q: A solenoid with 425 turns has a length of 5.50 cm and a cross-sectional area of 2.60 ✕ 10−9 m2. Find…

A: Given quantities: Number of turns (N) = 425 Length of the solenoid (d) = 5.50 cm Area of…

Q: A solenoid of radius 3.30 cm has 800 turns and a length of 15.0 cm. (a) Find its inductance. mH (b)…

A: Given:      Radius of the solenoid, r = 3.3 x 10-2 m…

Q: A solenoid with 495 turns has a length of 6.50 cm and a cross-sectional area of 3.10 x 10-9 m². Find…

A: If the number of loops is increased then magnetic fields are also increased in the case of…

Q: Find the cross-sectional area of a 5.1 cm long solenoid with 480 turns and a self-inductance of 44…

A: Length (L) = 5.1 cm = 0.051 m Number of turns (N) = 480Self inductance = 44 μH

Q: A solenoid of radius 2.70 cm has 580 turns and a length of 15.0 cm. (a) Find its inductance. mH (b)…

A: Given  radius of solenoid(r)=0.027 m so cross section arey(A)=0.00229 m2 turns(N)=580 length(l)=0.15…

Q: A coil of self-inductance 10 mH and resistance 0.1 Q is connected through a switch to a battery of…

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Q: A solenoid of radius 3.5 cm has 580 turns and a length of 25 cm. Find its inductance. ______mH…

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Q: A solenoid of radius 2.30 cm has 480 turns and a length of 15.0 cm. (a) Find its inductance. Apply…

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Q: A solenoid with 455 turns has a length of 6.50 cm and a cross-sectional area of 3.50 ✕ 10−9 m2. Find…

A: GivennN=455 turnsl=6.50 cm=0.065 mA=3.50×10-9 m2Current change from +2.50 A to -2.50 ATime…

Q: A solenoid with an inductance of 14 mH is charged up from an initial current of 3.0 A to a current…

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Q: A solenoid with 495 turns has a length of 8.00 cm and a cross-sectional area of 3.20 ✕ 10−9 m2. Find…

A: Required :  (a)the solenoid's inductance (in H)H(b)the average emf around the solenoid (in V)V

Q: A 30-cm-long cylindrical solenoid with a radius of 5.0 cm consists of 500 turns wrapped around its…

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Q: A solenoid with 455 turns has a length of 6.50 cm and a cross-sectional area of 2.60 ✕ 10−9 m2. Find…

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Q: A solenoid with 515 turns has a length of 5.50 cm and a cross-sectional area of 2.60 ✕ 10−9 m2. Find…

A: (a) The formula to calculate the inductance (L) is as follows: L=μ0N2Ad Thus, the inductance is,…

Q: A solenoid of radius 5 cm has 428 turns and a length of 38 cm. (a)  Find its inductance.  μ 0 = 4 π…

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Q: Consider a solenoid with a diameter 0.04 m, length 7.6 m, 55 turns, and total resistance 0.6 Ω. The…

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Q: QUESTION 1 If a current of 5A flowing in a coil of inductance 0.1H is reversed in 10ms, emf induced…

A: Note: According to our guideline, I am going to solve 1st question. Please post other questions…

Q: A solenoid with 485 turns has a length of 5.50 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find…

A: The inductance of the solenoid can be obtained as

Q: ») What is the characteristic time constant (in s) of a 25.5 mH inductor that has a resistance of…

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Q: with 435 turns has a length of 6.50 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the…

A: Given values:- Number of turns,(N)=435 Turns ----(1) Length of solenoid,(l)=6.50 cm=6.50 x 10-2 m…

Q: The current in the solenoid, whose inductance is L = 0.120 H, change in time according to the…

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Q: A solenoid filled with air contains 1500 turns and its cross sectional area is 6.0 cm. If the length…

A: Given  data: No. Of turns ( N ) = 1500  Cross sectional area ( A ) =6 cm2 = 6 × 10-4m2 Length of…

Q: A solenoid with 505 turns has a length of 8.00 cm and a cross-sectional area of 3.20 ✕ 10−9 m2. Find…

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Q: a = 10CM, b = 12 CM, h = 1CM, and N turns = 800, and free space permeability, then the…

A: Given data: a=10 cm; b=12 cm h=1 cm=0.01 m Number of turns, N=800 Free space permeability,…

Q: An air-core solenoid has N = 1525 turns, d = 0.37 m length, and cross sectional area A = 0.066 m2.…

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Q: Calculate the inductance of the very long conductive wire that carries current I and the conductive…

A: We need to calculate mutual inductance between the long wire and the shown loop.

Q: Find the energy stored in the magnetic field of an inductor having inductance 12.5 mH carrying the…

A: The expression for the stored energy is,

Q: A solenoid with 485 turns has a length of 5.50 cm and a cross-sectional area of 3.20 ✕ 10−9 m2. Find…

A: Given: The number of turns is 485. The cross-section area is 3.2x10-9 m2. The current changes from…

Q: A coil has a self-inductance of 50 [H] and a resistance of 3.5 [2]. It is connected to a 9.0 [V]…

A: self inductance (L) = 50 micro henryresistance (R) = 3.5 ohm resistance of the battery (r) = 0.25…

Q: In the figure R1 = 4.00 N , and R2 = When the switch is opened after having been closed for a long…

A: The current through the inductor when the switch is unplugged is given by  I=I0e-tτ rearrange the…

Q: Self-inductance (L) of a 40.0 cm long solenoid containing N = 400 turns, and cross-sectional area of…

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Q: A solenoid with a length of 45 cm is made by wrapping 450 wires around an iron rod has a…

A: Given, Length (L)=45cm Loop wire=450 Area of cross section=0.85cm² Relative permeability=350

Q: A solenoid with 495 turns has a length of 5.00 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find…

A: Given The number of turns of a solenoid is N=495 turns. The length of the solenoid is l=5 cm=5×10-2…

Q: A solenoid with 505 turns has a length of 6.50 cm and a cross-sectional area of 2.50 ✕ 10−9 m2. Find…

A: Number of turns,  N = 505  length, l = 6.5 cm  Area,  A = 2.5 x 10-9 m2 change in current, d I = 3.5…

Q: 5. A 500 turns solenoid develops an average induced voltage of 60 V. Over what time interval must a…

A: Answer:- (c) 0.5 s  Given  Number of turns (N) = 500  Induced voltage (E) = 60 V  Magnetic flux (d…

Q: The voltage across an inductor is 4.0 x 10-6V when the current through it decreased at a rate of…

A: Given:Voltage, V = 4×106 Vdidt = 4 A/s

Q: A solenoid with 455 turns has a length of 8.00 cm and a cross-sectional area of 2.70 ✕ 10−9 m2. Find…

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Voltage Across Inductor

An actor is a passive electrical component that consists of a coil bent in the form of wire which uses electromagnetism to produce electric current through the coil. When the electric current flows through a conductor that is the coil, a magnetic flux is developed around the conductor. This flow of current through the coil creates a magnetic field based on Fleming's Right-hand thumb rule. If there is any decrease in the current passing through the inductor, then the magnetic field will also decrease and energy is released through the generation of electric current. There is also a secondary voltage inducing in the same coil due to the magnetic flux, since it opposes any changes in the electric current flowing through the circuit. An inductor is also called choke, coil, or solenoid. A choke is designed to block certain frequencies when the DC current passes. A winding coil is coated with insulation to give extra insulation and protect the circuit. They are usually tightly wrapped around a central core which is cylindrical in nature so that the magnetic flux can be induced. The solenoid is a three-dimension coil that is used to exhibit electromagnetism when the magnetic field is developed due to the current flowing through the coil. The sign convention of the inductor is the same as the power dissipating device. When the current flows into the positive side of the voltage across the inductor, the value is positive and the inductor dissipates power whereas when the inductor releases the power back to the circuit, the current has a negative sign convention.