   Chapter 20, Problem 3P

Chapter
Section
Textbook Problem

Figure P20.3 shows three edge views of a square loop with sides of length ℓ = 0.250 m in a magnetic field of magnitude 2.00 T. Calculate the magnetic flux through the loop oriented (a) perpendicular to the magnetic field, (b) 60.0° from the magnetic field, and (c) parallel to the magnetic field. Figure P20.3

(a)

To determine
The flux when the loop is perpendicular to the magnetic field.

Explanation

Given info: The magnetic field of (B) is 2.00 T. Length of the square loop (l) is 0.250 m.

Formula to calculate flux is,

ϕB=BAcosθ

• θ is the angle between the field and area vector.

The area of the square loop is,

A=l2

Therefore,

ϕB=Bl2cosθ

Substitute 2.00 T for B,0.250 m for l and 0ο for θ

(b)

To determine
The flux when the loop makes 60ο angle with the magnetic field.

(c)

To determine
The flux when the loop is parallel to the magnetic field.

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