# Calculate the temperature in °C at which the equilibrium constant ( K ) for the following reaction is 1.00. MnO 2 ( s ) → Mn ( s ) + O 2 ( g )

### Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
Publisher: Cengage Learning
ISBN: 9781305079373

Chapter
Section

### Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
Publisher: Cengage Learning
ISBN: 9781305079373
Chapter 20, Problem 44QAP
Textbook Problem
1 views

## Calculate the temperature in °C at which the equilibrium constant (K) for the following reaction is 1.00.    MnO 2 ( s ) → Mn ( s ) + O 2 ( g )

Interpretation Introduction

Interpretation:

The temperature should be calculated in ? for the given system.

Concept introduction:

The temperature for any reaction can be easily obtained using Gibb’s equation:

ΔG0=ΔH0TΔS0

Where H is enthalpy, T is temperature and S is entropy of the reaction.

Further the change in enthalpy and entropy for reactions are obtained as:

ΔH0=ΔHf(products)0-ΔHf(reactants)0ΔS0=ΔS298(products)0-ΔS298(reactants)0

### Explanation of Solution

Given Information:

The equilibrium constant for the reaction is K=1.00

The reaction is MnO2(s)Mn(s)+O2(g)

The reaction is taken at equilibrium MnO2(s)Mn(s)+O2(g)

The Gibb’s free energy change for equilibrium conditions is taken as zero.

For this reaction type, the equation will become:

ΔG0=ΔH0TΔS00=ΔH0TΔS0ΔH0=TΔS0T=ΔH0ΔS0

Now, the standard enthalpy and entropy change will be calculated for the reaction as follows:

ΔH0=

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