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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

For the RnFx compounds you predicted in Exercise 71, give the molecular structure (including bond angles).

Interpretation Introduction

Interpretation: The molecular structures (including bond angles) for the predicted RnFx compounds in exercise 71 are to be stated.

Concept introduction: The following steps are to be followed to determine the molecular structure of a given compound,

  • The central atom is identified.
  • Its valence electrons are determined.
  • The value 1e is added to the total number of valence electrons for each monovalent atom present.
  • The total number obtained is divided by 2 to find the number of electron pairs.
  • This further gives the hybridization of the given compound.

To determine: The molecular structures (including bond angles) for the predicted RnFx compounds in exercise 71 .

Explanation

The Lewis structure, molecular structure, bond angle and hybridization of central atom in RnF2 is as follows.

Refer to exercise 71 .

The predicted RnFx compounds in exercise 71 are RnF2,RnF4 and RnF6 .

For RnF2 ,

The first step in determining the Lewis structure is to determine the number of valence electrons. The atomic number of central atom radon (Rn) is 86 and its electronic configuration is,

1s22s22p63s23p63d104s24p64d105s25p64f145d106s26p6

The valence electron of radon is 8 .

The atomic number of fluorine (F) is 9 and its electronic configuration is,

1s22s22p5

The valence electron of fluorine is 7 .

The molecule RnF2 is made of two fluorine atoms and single radon atom; hence, the total number of valence electrons is,

Rn+2F=(8+2×7)e=22e

The formula of number of electron pairs is,

X=V+M±C2

Where,

  • X is the number of electron pairs.
  • V is the valence electrons of central atom.
  • M is the number of monovalent atoms.
  • C is the charge on compound.

The number of electron pairs is,

X=V+M±C2X=102=5

This means that the central atom shows sp3d hybridization and should have a trigonal bipyramid geometry. But due to presence of repulsive force between lone pairs, the structure becomes linear shaped with the bond angle 180° .

The molecular structure of RnF2 is,

Figure 1

The Lewis structure, molecular structure, bond angle and hybridization of central atom in RnF4 is as follows.

For RnF4 ,

The first step in determining the Lewis structure is to determine the number of valence electrons. The atomic number of central atom radon (Rn) is 86 and its electronic configuration is,

1s22s22p63s23p63d104s24p64d105s25p64f145d106s26p6

The valence electron of radon is 8

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