(a) Interpretation: The glycosidic linkage in cellobiose should be located. Concept Introduction: Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

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Answer 1

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Students have asked these similar questions

(a) Locate the glycosidic linkage in cellobiose. (b) Number the carbon atoms in both rings. (c) Classify the glycosidic linkage as α or β, and use numbers to designate its location.

a. Identify the glycosidic linkage in disaccharide C, classify the glycosidic bond as α or β, and use numbers to designate its location.b. Identify the lettered compounds in the following reaction.

Cellobiose, a disaccharide obtained by the hydrolysis of cellulose, is composed of two glucose units joined by a 1→4-β-glycoside bond. What is the structure of cellobiose?

Answer 2

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Answer 3

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Answer 4

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Answer 5

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 6

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Answer 7

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 20.1 - Label the hemiacetal carbonthe carbon bonded to...Ch. 20.2 - Prob. 20.1PP Ch. 20.2 - Prob. 20.2P Ch. 20.2 - Prob. 20.3P Ch. 20.2 - Prob. 20.4P Ch. 20.2 - Prob. 20.5P Ch. 20.2 - Prob. 20.2PP Ch. 20.2 - Prob. 20.6P Ch. 20.2 - Prob. 20.7P Ch. 20.3 - Prob. 20.8P

Solution Summary: The author explains that the glycosidic linkage in cellobiose should be located.

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