Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 20.SE, Problem 38AP
Interpretation Introduction

a) lactic acid, Ka = 8.4 x 10-4

Interpretation:

The pKa of lactic acid with Ka = 8.4 x 10-4 is to be calculated.

Concept introduction:

pKa = - log Ka. By taking the inverse of log of Ka the pKa value can be obtained.

To calculate:

The pKa of lactic acid with Ka = 8.4 x 10-4.

Interpretation Introduction

b) Acrylic acid, Ka = 5.6 x 10-6

Interpretation:

The pKa of acrylic acid with Ka = 5.6 x 10-6 is to be calculated.

Concept introduction:

pKa = - log Ka. By taking the inverse of log of Ka the pKa value can be obtained.

To calculate:

The pKa of acrylic acid with Ka = 5.6 x 10-6.

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Chapter 20 Solutions

Organic Chemistry

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