# To evaluate h ( x ) = t + 1 t at a number, we substitute the number for t in the definition of h ( t ) .

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 2.1, Problem 22E
To determine

## To evaluate h(x)=t+1t at a number, we substitute the number for t in the definition of h(t) .

Expert Solution

The values of the given functionare:

h(1)=2,h(1)=2,h(2)=2.5,h(12)=2.5,h(x)=x+1x,h(1x)=1x+x

### Explanation of Solution

Given information: consider the function h(x)=t+1t

Calculation:

Evaluate the values of the function h(x)=t+1t for the given values of the variable t

Plug the value t=1, in the function h(x)=t+1t then we get the value of h(1).

h(1)=1+11h(1)=1+1h(1)=2

Plug the value t=1, in the function h(x)=t+1t then we get the value of h(1).

h(1)=1+11h(1)=11h(1)=2

Plug the value t=2 in the function h(x)=t+1t then we get the value of h(2).

h(2)=2+12h(2)=4+12h(2)=52h(2)=2.5

Plug the value t=12, in the function h(x)=t+1t then we get the value of h(12).

h(12)=12+112h(12)=0.5+2h(12)=2.5

Plug the value t=x, in the function h(x)=t+1t then we get the value of h(x).

h(x)=x+1xh(x)=x+1x

Plug the value t=1x, in the function h(x)=t+1t then we get the value of h(1x).

h(1x)=1x+11xh(1x)=1x+x

Thus, the values of the given function are:

h(1)=2,h(1)=2,h(2)=2.5,h(12)=2.5,h(x)=x+1x,h(1x)=1x+x

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