Given information: consider the function h(x)=t+1t
Calculation:
Evaluate the values of the function h(x)=t+1t for the given values of the variable t
Plug the value t=1, in the function h(x)=t+1t then we get the value of h(1).
h(1)=1+11h(1)=1+1h(1)=2
Plug the value t=−1, in the function h(x)=t+1t then we get the value of h(−1).
h(−1)=−1+1−1h(1)=−1−1h(1)=−2
Plug the value t=2 in the function h(x)=t+1t then we get the value of h(2).
h(2)=2+12h(2)=4+12h(2)=52h(2)=2.5
Plug the value t=12, in the function h(x)=t+1t then we get the value of h(12).
h(12)=12+112h(12)=0.5+2h(12)=2.5
Plug the value t=x, in the function h(x)=t+1t then we get the value of h(x).
h(x)=x+1xh(x)=x+1x
Plug the value t=1x, in the function h(x)=t+1t then we get the value of h(1x).
h(1x)=1x+11xh(1x)=1x+x
Thus, the values of the given function are:
h(1)=2,h(−1)=−2,h(2)=2.5,h(12)=2.5,h(x)=x+1x,h(1x)=1x+x