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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

A method recently suggested for the preparation of hydrogen (and oxygen) from water proceeds as follows:

  1. (a) Sulfuric acid and hydrogen iodide are formed from sulfur dioxide, water, and iodine.
  2. (b) The sulfuric acid from the first step is decomposed by heat to water, sulfur dioxide, and oxygen.
  3. (c) The hydrogen iodide from the first step is decomposed with heat to hydrogen and iodine.

Write a balanced equation for each of these steps, and show that their sum is the decomposition of water to form hydrogen and oxygen.

Interpretation Introduction

Interpretation:

To write the balanced chemical equation for each of the given steps and show that their sum is decomposition of water to produce hydrogen and oxygen.

Concept introduction: Hydrogen can be produced by a recently suggested method. It is a three-step process and is known as a sulfur-iodine cycle. The cycle starts with sulfur dioxide, water and iodine to form sulfuric acid and hydrogen iodide. Sulfuric acid decomposed to water, sulfur dioxide and oxygen. Hydrogen iodide is decomposed into hydrogen and iodine.

The net reaction of these three steps is the decomposition of water to hydrogen and oxygen.

However, an efficient source of heat is required for this process.

There are some disadvantages to this method. A very high-temperature condition is required and the reagents used are corrosive.

Explanation

Balanced equations for each of the given reaction are written below,

(a)

The balanced chemical equation for the reaction of sulfur dioxide, water and iodine to form hydrogen iodide and sulfuric acid is:

    SO2(g)+2H2O(l)+I2(s)H2SO4(l)+2HI(g)

The sulfur-iodine cycle starts with the reagents sulfur dioxide, water and iodine. They combine to form sulfuric acid and hydrogen iodide. The stoichiometric coefficients are multiplied with species to have an equal number of atoms on both the reactant and product side, for a balanced chemical equation. Since iodine is present as I2 in the reaction, hence the stoichiometric coefficient of HI is 2 due to which water also has a stoichiometric coefficient of 2 .

Hence, the balanced chemical equation for the reaction of sulfur dioxide, water and iodine to form hydrogen iodide and sulfuric acid is:

    SO2(g) + 2H2O(l) + I2(s)H2SO4(l)+ 2HI(g)

(b)

The balanced chemical equation for the decomposition of sulfuric acid by heat to water, sulfur dioxide and oxygen is:

    H2SO4(l)ΔH2O(l)+SO2(g)+12O2(g)

The sulfur-iodine cycle starts with the reagents sulfur dioxide, water and iodine. They combine to form sulfuric acid and hydrogen iodide. The sulfuric acid formed is step (a) is decomposed to form water, sulfur dioxide and oxygen. The stoichiometric coefficients are multiplied with species to have an equal number of atoms on both the reactant and product side, for a balanced chemical equation. The number of oxygen atoms on the reactant side is 4 and on the product side is 5. Thus, the stoichiometric coefficient of 12 is multiplied by oxygen

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Chapter 21 Solutions

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Sect-21.11 P-2.4ACPSect-21.11 P-2.5ACPCh-21 P-1PSCh-21 P-2PSCh-21 P-3PSCh-21 P-4PSCh-21 P-5PSCh-21 P-6PSCh-21 P-7PSCh-21 P-8PSCh-21 P-9PSCh-21 P-10PSCh-21 P-11PSCh-21 P-12PSCh-21 P-13PSCh-21 P-14PSCh-21 P-15PSCh-21 P-16PSCh-21 P-17PSCh-21 P-18PSCh-21 P-19PSCh-21 P-20PSCh-21 P-21PSCh-21 P-22PSCh-21 P-23PSCh-21 P-24PSCh-21 P-25PSCh-21 P-26PSCh-21 P-27PSCh-21 P-28PSCh-21 P-29PSCh-21 P-30PSCh-21 P-31PSCh-21 P-32PSCh-21 P-33PSCh-21 P-34PSCh-21 P-35PSCh-21 P-36PSCh-21 P-37PSCh-21 P-38PSCh-21 P-39PSCh-21 P-40PSCh-21 P-41PSCh-21 P-42PSCh-21 P-43PSCh-21 P-44PSCh-21 P-45PSCh-21 P-46PSCh-21 P-47PSCh-21 P-48PSCh-21 P-49PSCh-21 P-50PSCh-21 P-51PSCh-21 P-52PSCh-21 P-53PSCh-21 P-54PSCh-21 P-55PSCh-21 P-56PSCh-21 P-57PSCh-21 P-58PSCh-21 P-59PSCh-21 P-60PSCh-21 P-61PSCh-21 P-62PSCh-21 P-63PSCh-21 P-64PSCh-21 P-65PSCh-21 P-66PSCh-21 P-67PSCh-21 P-68PSCh-21 P-69PSCh-21 P-70PSCh-21 P-71PSCh-21 P-72PSCh-21 P-73PSCh-21 P-74PSCh-21 P-75PSCh-21 P-76PSCh-21 P-77PSCh-21 P-78PSCh-21 P-79PSCh-21 P-80PSCh-21 P-81PSCh-21 P-82PSCh-21 P-83PSCh-21 P-84PSCh-21 P-85PSCh-21 P-86PSCh-21 P-87PSCh-21 P-88PSCh-21 P-89GQCh-21 P-90GQCh-21 P-91GQCh-21 P-92GQCh-21 P-93GQCh-21 P-94GQCh-21 P-95GQCh-21 P-96GQCh-21 P-97GQCh-21 P-98GQCh-21 P-99GQCh-21 P-100GQCh-21 P-101GQCh-21 P-102GQCh-21 P-103GQCh-21 P-105GQCh-21 P-106GQCh-21 P-107GQCh-21 P-108GQCh-21 P-110GQCh-21 P-111GQCh-21 P-112GQCh-21 P-113GQCh-21 P-114GQCh-21 P-115ILCh-21 P-116ILCh-21 P-117ILCh-21 P-118ILCh-21 P-119ILCh-21 P-120ILCh-21 P-121SCQCh-21 P-122SCQCh-21 P-123SCQCh-21 P-124SCQCh-21 P-125SCQCh-21 P-126SCQCh-21 P-127SCQCh-21 P-128SCQCh-21 P-129SCQCh-21 P-130SCQCh-21 P-131SCQ

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