   Chapter 21, Problem 26E

Chapter
Section
Textbook Problem

# What is the electron configuration for the transition metal ion(s) in each of the following compounds?a. (NH4)2[Fe(H2O)2Cl4]b. [Co(NH3)2(NH2CH2CH2NH2)2]I2c. Na2[TaF7]d. [Pt(NH3)4I2][PtI4]Pt forms +2 and +4 oxidation states in compounds.

Interpretation Introduction

Interpretation: The electron configuration of metal ion in each given complex compound is to be stated.

Concept introduction: Valence electrons are filled in four principal orbitals according to the energy levels. The four orbitals are s,p,d and f .

The metals from group 3-12 are known as first row transition metals. The general form of valence electron configuration of these metals is,

[Nobelgas]nfxndynsz

The distribution of electrons among different orbitals is given by electron configuration. When an element loses an electron, a positive charge is accumulated on it, whereas when an element gains an electron, negative charge is accumulated on it.

Explanation

EXPLANATION

(a)

To write: The electron configuration of metal ion in (NH4)2[Fe(H2O)2Cl4] .

The metals from group 3-12 are known as first row transition metals. The general form of valence electron configuration of these metals is,

[Nobelgas]nfxndynsz

Where,

• n is the shell of principal orbital.
• x is the number of electrons in f orbital.
• y is the number of electrons in d orbital.
• z is the number of electrons in s orbital.

In the complex compound (NH4)2[Fe(H2O)2Cl4] , the metal ion is Fe2+ .

Iron is a group 8 element. The atomic number of iron (Fe) is 26 and its electronic configuration is,

[Ar]3d64s2

It loses two electrons to acquire two positive charges and becomes Fe2+ . The electronic configuration of Fe2+ is,

Fe2+=Fe2e

Substitute the electron configuration of Fe in the above equation.

Fe2+=Fe2e=[Ar]3d64s22e=[Ar]3d6

(b)

To write: The electron configuration of metal ion in [Co(NH3)2(NH2CH2CH2NH2)]I2 .

In the complex compound [Ag(NH3)2]Cl , metal ion is Co2+ .

Cobalt is a group 9 element. The atomic number of cobalt (Co) is 27 and its electronic configuration is,

[Ar]3d74s2

It loses two electrons to acquire two positive charges and becomes Co2+ . The electronic configuration of Co2+ is,

Co2+=Co2e

Substitute the electron configuration of Co in the above equation.

Co2+=Co2e=[Ar]3d74s22e=[Ar]3d7

(c)

To write: The electron configuration of metal ion in Na2[TaF7]

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