# To evaluate f ( − 4 ) , f ( − 3 2 ) , f ( − 1 ) , f ( 0 ) , f ( 25 ) values use the piecewise function f ( x ) = { x 2 + 2 x , if x ≤ − 1 x , if − 1 &lt; x ≤ 1 − 1 , if x &gt; 1 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071 ### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 2.1, Problem 29E
To determine

## To evaluate f(−4),f(−32),f(−1),f(0),f(25) values use the piecewise function  f(x)={x2+2x,            if  x≤−1x,                     if −1<x≤1−1,                   if  x>1

Expert Solution

The required functions of the values are

f(4)=8,f(32)=34,f(1)=1,f(0)=0,f(25)=1

### Explanation of Solution

Given information: consider the piecewise function f(x)={x2+2x,            if  x1x,                     if 1<x11,                   if  x>1

Calculation:

First find the value of f(4),f(32),f(1)

Since the values of x=4<1,x=32<1 and x=1

From the above piecewise function, to be taken as

f(x)=x2+2x

f(4)=(4)2+2(4)f(4)=8

f(32)=(32)2+2(32)f(32)=943f(32)=34

f(1)=(1)2+2(1)f(1)=1

Find the value of f(0)

Since the value of x=0<1

From the above piecewise function, to be taken as

f(x)=x

f(0)=0

Find the value of f(25)

Since the value of x=25>1

From the above piecewise function, to be taken as

f(x)=1

f(25)=1

Thus the required function of the values

f(4)=8,f(32)=34,f(1)=1,f(0)=0,f(25)=1

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