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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

The CrF64− ion is known to have four unpaired electrons. Does the F ligand produce a strong or weak field?

Interpretation Introduction

Interpretation: It is given that, the CrF64  ion is known to have four unpaired electrons. If F ion produces a strong or weak field is to be stated.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to the presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to the presence of maximum paired electrons in lower energy t2g orbitals.

To determine: If F ion produces a strong or weak field.

Explanation

Explanation

The complex ion CrF64  ion is known to have four unpaired electrons.

Oxidation state of Fluorine ion (F) is 1 .

It is assumed that the oxidation state of metal ion Chromium (Cr) is x .

The given complex compound contains six Fluorine ions. Since, the overall charge on  the complex ion is 4 . Therefore,

6(1)+x=4x=+2

Therefore, the oxidation state of Chromium is +2 .

The F ion produces a weak field.

The atomic number of Chromium is 24 and its electronic configuration is,

[Ar]3d54s1

It loses two electrons to acquire two positive charge and becomes Cr2+

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