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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

Give examples of two acidic oxides. Write equations illustrating the formation of each oxide from its component elements. Write another chemical equation that illustrates the acidic character of each oxide.

Interpretation Introduction

Interpretation: Examples for two acidic oxides has to be given. Equations illustrating the formation of each oxide from its component elements should be written.

Concept introduction: Oxides are formed by reaction of metal with oxygen. An acidic oxide is an oxide that shows acidic properties in solution. If an element E belongs to group 6A of periodic table, then the general reaction of formation of oxide is:

    E(s)+ O2(g)EO2(g)

Acidic oxides on reaction with water form an acid. This is a characteristic property of acidic oxides and thus illustrates its acidic behavior. Acidic oxides are mostly oxides of group 5A and 6A elements. Thus, acidic oxides are generally oxides of non-metals and they react with water to form acids. The general reaction of a non-metal oxide with water is as follows:

    EO2(g)+H2O(l)HEO3(aq)+ HEO2(aq)

Here, E is any element of group 5A or 6A of the periodic table.

Explanation

Acidic oxides are generally oxides of non-metals of group 5A and 6A metals. The two examples of acidic oxide are NO2 and SO3.

Both the oxides are formed in the presence of excess oxygen. Nitrogen dioxide is formed by reaction of nitrogen monoxide formed by reaction of nitrogen with oxygen, with atmospheric oxygen. Sulfur trioxide is formed by the reaction of sulfur dioxide with oxygen.

Thus, the balanced chemical equation is:

  • For NO2,

    N2(g)+ O2(g)2NO(g)2NO(g)+O2(g)2NO2(g)

  • For SO3,

    S(g)+O2(g)SO2(g)SO2(g)+12O2(g)SO3(g)

The stoichiometric coefficients are multiplied with the compounds in the chemical equation to have an equal number of atoms on both sides of the equation. Since oxygen is present as O2 and nitrogen is present as N2    in the reaction, hence the stoichiometric coefficient of non-metal oxide, NO is 2

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Chapter 21 Solutions

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Sect-21.11 P-2.4ACPSect-21.11 P-2.5ACPCh-21 P-1PSCh-21 P-2PSCh-21 P-3PSCh-21 P-4PSCh-21 P-5PSCh-21 P-6PSCh-21 P-7PSCh-21 P-8PSCh-21 P-9PSCh-21 P-10PSCh-21 P-11PSCh-21 P-12PSCh-21 P-13PSCh-21 P-14PSCh-21 P-15PSCh-21 P-16PSCh-21 P-17PSCh-21 P-18PSCh-21 P-19PSCh-21 P-20PSCh-21 P-21PSCh-21 P-22PSCh-21 P-23PSCh-21 P-24PSCh-21 P-25PSCh-21 P-26PSCh-21 P-27PSCh-21 P-28PSCh-21 P-29PSCh-21 P-30PSCh-21 P-31PSCh-21 P-32PSCh-21 P-33PSCh-21 P-34PSCh-21 P-35PSCh-21 P-36PSCh-21 P-37PSCh-21 P-38PSCh-21 P-39PSCh-21 P-40PSCh-21 P-41PSCh-21 P-42PSCh-21 P-43PSCh-21 P-44PSCh-21 P-45PSCh-21 P-46PSCh-21 P-47PSCh-21 P-48PSCh-21 P-49PSCh-21 P-50PSCh-21 P-51PSCh-21 P-52PSCh-21 P-53PSCh-21 P-54PSCh-21 P-55PSCh-21 P-56PSCh-21 P-57PSCh-21 P-58PSCh-21 P-59PSCh-21 P-60PSCh-21 P-61PSCh-21 P-62PSCh-21 P-63PSCh-21 P-64PSCh-21 P-65PSCh-21 P-66PSCh-21 P-67PSCh-21 P-68PSCh-21 P-69PSCh-21 P-70PSCh-21 P-71PSCh-21 P-72PSCh-21 P-73PSCh-21 P-74PSCh-21 P-75PSCh-21 P-76PSCh-21 P-77PSCh-21 P-78PSCh-21 P-79PSCh-21 P-80PSCh-21 P-81PSCh-21 P-82PSCh-21 P-83PSCh-21 P-84PSCh-21 P-85PSCh-21 P-86PSCh-21 P-87PSCh-21 P-88PSCh-21 P-89GQCh-21 P-90GQCh-21 P-91GQCh-21 P-92GQCh-21 P-93GQCh-21 P-94GQCh-21 P-95GQCh-21 P-96GQCh-21 P-97GQCh-21 P-98GQCh-21 P-99GQCh-21 P-100GQCh-21 P-101GQCh-21 P-102GQCh-21 P-103GQCh-21 P-105GQCh-21 P-106GQCh-21 P-107GQCh-21 P-108GQCh-21 P-110GQCh-21 P-111GQCh-21 P-112GQCh-21 P-113GQCh-21 P-114GQCh-21 P-115ILCh-21 P-116ILCh-21 P-117ILCh-21 P-118ILCh-21 P-119ILCh-21 P-120ILCh-21 P-121SCQCh-21 P-122SCQCh-21 P-123SCQCh-21 P-124SCQCh-21 P-125SCQCh-21 P-126SCQCh-21 P-127SCQCh-21 P-128SCQCh-21 P-129SCQCh-21 P-130SCQCh-21 P-131SCQ

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