Using curved arrows, show how the species in part (a) can act as Lewis bases in their reactions with HGl, and show how the species in part (b) can act as Lewis acids in their reaction with OH - . (a) CH 3 CH 2 OH, HN(CH 3 ) 2 , P(CH 3 ) 3 (b) H 3 C + , B(CH 3 ) 3 , MgBr 2

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Interpretation Introduction a) CH 3 CH 2 OH, HN(CH 3 ) 2 , P(CH 3 ) 3 Interpretation: Using curved arrows how the species, CH 3 CH 2 OH, HN(CH 3 ) 2 , P(CH 3 ) 3 can act as Lewis bases in their reactions with HCl is to be shown. Concept introduction: A Lewis base is a substance that donates an electron pair to other substances. Therefore in the species given the atom with lone pair of electrons is to be located. Curved arrows are to be used to show the movement of electron pair from that atom towards the hydrogen atom of the acid. To show: Using curved arrows how the species, CH 3 CH 2 OH, HN(CH 3 ) 2 , P(CH 3 ) 3 can act as Lewis bases in their reactions with HCl. Explanation CH 3 CH 2 OH has an oxygen atom. Oxygen has six valence electrons out of which two are utilized for forming bonds with H and C and it has the remaining four electrons as two lone pairs. It can donate the lone pair of electrons to the hydrogen of HCl. Thus CH 3 CH 2 OH can act as a Lewis base. HN(CH 3 ) 2 hasÂ one nitrogen atom. Nitrogen has five valence electrons out of which three are utilized to form bonds with H and two carbons and it has the remaining two electrons as lone pair... Interpretation Introduction b) CH 3 + , B(CH 3 ) 3 , MgBr 2 Interpretation: Using curved arrows how the species, CH 3 + , B(CH 3 ) 3 , MgBr 2 can act as Lewis acids in their reactions with OH - is to be shown. Concept introduction: A Lewis acid is a substance that accepts an electron pair from other substances. Therefore in the species given an electron deficient atom which can accept an electron pair is to be located. Curved arrows are to be used to show the movement of electron pair from the donor towards the electron deficient atom. To show: Using curved arrows how the species, CH 3 + , B(CH 3 ) 3 , MgBr 2 can act as Lewis acids in their reactions with OH - is to be shown.

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Answer 1

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Organic Chemistry

9th Edition

John E. McMurry

Publisher: Cengage Learning

ISBN: 9781305080485

Solutions

Chapter

Section

Problem 17P

Problem 18P

Answer 2

BuyFind

Organic Chemistry

9th Edition

John E. McMurry

Publisher: Cengage Learning

ISBN: 9781305080485

Solutions

Chapter

Section

Problem 17P

Problem 18P

Answer 3

Solutions

Chapter

Section

Problem 17P

Problem 18P

Answer 4

Chapter

Section

Answer 5

Interpretation Introduction

a) CH₃CH₂OH, HN(CH₃)₂, P(CH₃)₃

Interpretation:

Using curved arrows how the species, CH₃CH₂OH, HN(CH₃)₂, P(CH₃)₃ can act as Lewis bases in their reactions with HCl is to be shown.

Concept introduction:

A Lewis base is a substance that donates an electron pair to other substances. Therefore in the species given the atom with lone pair of electrons is to be located. Curved arrows are to be used to show the movement of electron pair from that atom towards the hydrogen atom of the acid.

To show:

Using curved arrows how the species, CH₃CH₂OH, HN(CH₃)₂, P(CH₃)₃ can act as Lewis bases in their reactions with HCl.

Explanation of Solution

CH₃CH₂OH has an oxygen atom. Oxygen has six valence electrons out of which two are utilized for forming bonds with H and C and it has the remaining four electrons as two lone pairs. It can donate the lone pair of electrons to the hydrogen of HCl. Thus CH₃CH₂OH can act as a Lewis base.

HN(CH₃)₂ hasÂ one nitrogen atom. Nitrogen has five valence electrons out of which three are utilized to form bonds with H and two carbons and it has the remaining two electrons as lone pair...

Answer 6

Interpretation Introduction

b) CH₃⁺, B(CH₃)₃, MgBr₂

Interpretation:

Using curved arrows how the species, CH₃⁺, B(CH₃)₃, MgBr₂ can act as Lewis acids in their reactions with OH^- is to be shown.

Concept introduction:

A Lewis acid is a substance that accepts an electron pair from other substances. Therefore in the species given an electron deficient atom which can accept an electron pair is to be located. Curved arrows are to be used to show the movement of electron pair from the donor towards the electron deficient atom.

To show:

Using curved arrows how the species, CH₃⁺, B(CH₃)₃, MgBr₂ can act as Lewis acids in their reactions with OH^- is to be shown.

Using curved arrows, show how the species in part (a) can act as Lewis bases in their reactions with HGl, and show how the species in part (b) can act as Lewis acids in their reaction with OH - . (a) CH 3 CH 2 OH, HN(CH 3 ) 2 , P(CH 3 ) 3 (b) H 3 C + , B(CH 3 ) 3 , MgBr 2

Organic Chemistry

Solutions

Organic Chemistry

Using curved arrows, show how the species in part (a) can act as Lewis bases in their reactions with HGl, and show how the species in part (b) can act as Lewis acids in their reaction with OH^-.

(a) CH₃CH₂OH, HN(CH₃)₂, P(CH₃)₃

(b) H₃C⁺, B(CH₃)₃, MgBr₂

Explanation of Solution

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Using curved arrows, show how the species in part (a) can act as Lewis bases in their reactions with HGl, and show how the species in part (b) can act as Lewis acids in their reaction with OH - . (a) CH 3 CH 2 OH, HN(CH 3 ) 2 , P(CH 3 ) 3 (b) H 3 C + , B(CH 3 ) 3 , MgBr 2

Organic Chemistry

Solutions

Organic Chemistry