   Chapter 21.11, Problem 2.4ACP

Chapter
Section
Textbook Problem

The best catalysts used to accelerate the decomposition of ammonia borane result in release of 140 g H2 per kg. What proportion of hydrogen is released?

Interpretation Introduction

Interpretation:

To calculate the proportion of hydrogen released on decomposition of ammonia borane.

Concept introduction:

The formula for ammonia borane is H3NBH3. It is an important boron-nitrogen hydride compound and is a source of hydrogen fuel. The other name for ammonia borane is borazane.

It is a colorless white solid and has an atomic mass of 30.865 g.

d=mV

d is the density, m is the mass and v is the volume

Explanation

The proportion of hydrogen released on decomposition of ammonia borane is calculated below.

Given:

The density of ammonia borane is 0.780 g/cm3.

d=mV

For 1 L of solution, the mass of ammonia borane is expressed as,

m=d×V

Substitute the values,

m=(0.780 g/cm3)(1000 cm3)m=780 g

Now,

The molar mass of ammonia borane is 30.865 g.

The atomic mass of six hydrogen atom is 6.047 g.

Thus, the percent of the mass of hydrogen in ammonia borane is:

Percent H=6.047g30

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