Explanation According to the Kirchhoff’s voltage law, the total voltage around the loop is equal to the sum of all the voltage drops within the same loop which is also equal to zero. The algebraic sum of all voltages within the loop must be equal to zero. Apply the Kirchhoff’s voltage rule in loop 1 of the circuit. 12 V − ( 200 Ω ) I 3 − ( 300 Ω ) I 1 = 0 Conclusion: The calculated statement of Kirchhoff’s rules for loop 1 is 12 V − ( 200 Ω ) I 3 − ( 300 Ω ) I 1 = 0 . In option (d), the statement of Kirchhoff’s rules for loop 1 is 12 V − ( 200 Ω ) I 3 − ( 300 Ω ) I 1 = 0 . Thus, the option (d) is correct. The calculated statement of Kirchhoff’s rules for loop 1 is 12 V − ( 200 Ω ) I 3 − ( 300 Ω ) I 1 = 0 . In option (a), the statement of Kirchhoff’s rules for loop 1 is 12 V + ( 200 Ω ) I 2 + ( 300 Ω ) I 1 = 0

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Chapter 21.5, Problem 5EYU

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The correct statement of Kirchhoff’s rules for loop 1 .

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The correct statement of Kirchhoff’s rules for loop 1 .

Solution Summary: The author explains the correct statement of Kirchhoff's rules for loop 1 — the total voltage around the loop is equal to the sum of all the voltage drops within the same loop.

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The correct statement of Kirchhoff’s rules for loop 1 .

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