Single Variable Calculus: Early Tr...

8th Edition

James Stewart

ISBN: 9781305270343

Textbook Problem

Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places).

lim x → − 3 x 2 − 3 x x 2 − 9 ,

x= –2.5, –2.9, –2.95, –2.99, –2.999, –2.9999, –3.5, –3.1, –3.05, –3.01, –3.001, –3.0001

To determine

To guess: The value of limx→−3x2−3xx2−9.

Explanation

Given:

The values of x are −2.5,−2.9,−2.95,−2.99,−2.999,−2.9999,−3.5,−3.1,−3.05,−3.01,

−3.001 and −3.0001.

Calculation:

Since x approaches −3, the values −3.5,−3.1,−3.05,−3.01,−3.001 and −3.0001 are to the left of −3 and the values −2.5,−2.9,−2.95,−2.99,−2.999, and−2.9999 are to the right of −3.

x	x2−3x	x2−9	f(x)=x2−3xx2−9
−3.5	22.75	3.25	7
−3.1	18.91	0.61	31
−3.05	18.4525	0.3025	61
−3.01	18.0901	0.0601	301
−3.001	18.009	0.006001	3,001
−3.0001	18.0009	0.0006	30,001

MathCalculusSingle Variable Calculus: Early Transcendentals, Volume I8th Edition

Single Variable Calculus: Early Tr...

Solutions

Single Variable Calculus: Early Tr...

Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places). lim x → − 3 x 2 − 3 x x 2 − 9 , x= –2.5, –2.9, –2.95, –2.99, –2.999, –2.9999, –3.5, –3.1, –3.05, –3.01, –3.001, –3.0001

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Math
Calculus Single Variable Calculus: Early Transcendentals, Volume I 8th Edition

Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places).

lim x → − 3 x 2 − 3 x x 2 − 9 ,

x= –2.5, –2.9, –2.95, –2.99, –2.999, –2.9999, –3.5, –3.1, –3.05, –3.01, –3.001, –3.0001